• [BZOJ2725/Violet 6]故乡的梦


    Description

    Input

    Output

    Sample Input
    6 7
    1 2 1
    2 3 1
    3 4 2
    4 5 1
    5 6 1
    1 3 3
    4 6 3
    1 6
    4
    1 2
    1 3
    4 3
    6 5

    Sample Output
    7
    6
    Infinity
    7

    HINT


    其实这题和[TJOI2012]桥基本差不多,如果不是最短路径上的边,那直接输出最短路即可。否则就按照[TJOI2012]桥那题来即可

    /*program from Wolfycz*/
    #include<cmath>
    #include<cstdio>
    #include<cstring>
    #include<iostream>
    #include<algorithm>
    #include<unordered_set>
    #define inf 0x7f7f7f7f7f7f7f7f
    using namespace std;
    typedef long long ll;
    typedef unsigned int ui;
    typedef unsigned long long ull;
    inline int read(){
    	int x=0,f=1;char ch=getchar();
    	for (;ch<'0'||ch>'9';ch=getchar())	if (ch=='-')    f=-1;
    	for (;ch>='0'&&ch<='9';ch=getchar())	x=(x<<1)+(x<<3)+ch-'0';
    	return x*f;
    }
    inline void print(int x){
    	if (x>=10)	print(x/10);
    	putchar(x%10+'0');
    }
    const int N=2e5,M=2e5;
    int pre[(M<<1)+10],now[N+10],child[(M<<1)+10],val[(M<<1)+10];
    int Fa[N+10],Lca[N+10],stack[N+10],dfn[N+10];
    bool vis[N+10],flag[(M<<1)+10];
    int n,m,tot,num,Max;
    ll Dis,Ans[N+10];
    struct MyHash{
    	size_t operator ()(const pair<int,int> &x)const{
    		return ((hash<int>()(x.first)<<1)^(hash<int>()(x.second)))>>1;
    	}
    };
    unordered_set<pair<int,int>,MyHash>st;
    struct S1{
    	#define ls (p<<1)
    	#define rs (p<<1|1)
    	#define fa (p>>1)
    	struct node{
    		int x;ll v;
    		bool operator <(const node &a)const{return v<a.v;}
    	}Q[N+10];
    	int tot;
    	void insert(int x,ll v){
    		Q[++tot]=(node){x,v};
    		int p=tot;
    		while (p!=1&&Q[p]<Q[fa])	swap(Q[p],Q[fa]),p=fa;
    	}
    	void Delete(){
    		Q[1]=Q[tot--];
    		int p=1,son;
    		while (ls<=tot){
    			if (rs>tot||Q[ls]<Q[rs])	son=ls;
    			else	son=rs;
    			if (Q[son]<Q[p])	swap(Q[p],Q[son]),p=son;
    			else	break;
    		}
    	}
    }Heap;
    struct Segment{
    	ll tree[(N<<2)+10];
    	Segment(){memset(tree,127,sizeof(tree));}
    	void Add_tag(int p,ll v){tree[p]=min(tree[p],v);}
    	void pushdown(int p){
    		if (tree[p]==inf)	return;
    		Add_tag(ls,tree[p]);
    		Add_tag(rs,tree[p]);
    	}
    	void Modify(int p,int l,int r,int x,int y,ll v){
    		if (x<=l&&r<=y){
    			Add_tag(p,v);
    			return;
    		}
    		int mid=(l+r)>>1;
    		if (x<=mid)	Modify(ls,l,mid,x,y,v);
    		if (y>mid)	Modify(rs,mid+1,r,x,y,v);
    	}
    	void traversals(int p,int l,int r){
    		if (l==r){
    			Ans[l]=tree[p];
    			return;
    		}
    		pushdown(p);
    		int mid=(l+r)>>1;
    		traversals(ls,l,mid);
    		traversals(rs,mid+1,r);
    	}
    }Tree;
    struct S2{
    	ll dis[N+10];
    	S2(){memset(dis,63,sizeof(dis));}
    }Frw,Bck;
    void join(int x,int y,int z){pre[++tot]=now[x],now[x]=tot,child[tot]=y,val[tot]=z;}
    void insert(int x,int y,int z){join(x,y,z),join(y,x,z);}
    void dijkstra(int x,ll *dis){
    	memset(vis,0,sizeof(vis));
    	Heap.insert(x,dis[x]=0);
    	while (Heap.tot){
    		int Now=Heap.Q[1].x;
    		Heap.Delete();
    		if (vis[Now])	continue;
    		vis[Now]=1;
    		for (int p=now[Now],son=child[p];p;p=pre[p],son=child[p]){
    			if (dis[son]>dis[Now]+val[p]){
    				dis[son]=dis[Now]+val[p];
    				Heap.insert(son,dis[son]);
    			}
    		}
    	}
    }
    void put_flag(int x){
    	for (int p=now[x],son=child[p];p;p=pre[p],son=child[p]){
    		if (Frw.dis[x]+val[p]+Bck.dis[son]==Dis){
    			st.insert(make_pair(x,son));
    			st.insert(make_pair(son,x));
    			flag[p]=flag[p+(p&1?1:-1)]=1;
    			put_flag(son);
    			return;
    		}
    	}
    }
    void Find_fa(int x){
    	for (int p=now[x],son=child[p];p;p=pre[p],son=child[p])
    		if (Frw.dis[x]+val[p]==Frw.dis[son]&&!Fa[son])	Fa[son]=x,Find_fa(son);
    }
    void Fill(int x,int v){
    	if (Lca[x])	return;
    	Lca[x]=v;
    	for (int p=now[x],son=child[p];p;p=pre[p],son=child[p])	if (Fa[son]==x)	Fill(son,v);
    }
    void Get_Lca(int x){
    	int top=0;
    	while (x){
    		Fill(x,x);
    		stack[++top]=x;
    		x=Fa[x];
    	}
    	for (int i=top;i;i--)	dfn[stack[i]]=num++;
    	num--;
    }
    int main(){
    	int n=read(),m=read();
    	for (int i=1;i<=m;i++){
    		int x=read(),y=read(),z=read();
    		insert(x,y,z);
    	}
    	int S=read(),T=read();
    	dijkstra(S,Frw.dis);
    	dijkstra(T,Bck.dis);
    	Dis=Frw.dis[T];
    	put_flag(S);
    	Find_fa(S);
    	Get_Lca(T);
    	for (int i=1;i<=tot;i+=2){
    		if (flag[i])	continue;
    		int x=child[i],y=child[i+1],v=val[i];
    		if (Lca[x]==Lca[y])	continue;
    		if (dfn[Lca[x]]>dfn[Lca[y]])	swap(x,y);
    		ll tmp=Frw.dis[x]+v+Bck.dis[y];
    		Tree.Modify(1,1,num,dfn[Lca[x]]+1,dfn[Lca[y]],tmp);
    	}
    	Tree.traversals(1,1,num);
    	int Q=read();
    	for (int i=1;i<=Q;i++){
    		int x=read(),y=read();
    		if (!st.count(make_pair(x,y))){
    			printf("%lld
    ",Dis);
    			continue;
    		}
    		printf(Ans[max(dfn[x],dfn[y])]==inf?"Infinity
    ":"%lld
    ",Ans[max(dfn[x],dfn[y])]);
    	}
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/Wolfycz/p/9745712.html
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