像瓜子样的曲线
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#http://www.mathcurve.com/courbes2d/clairaut/clairaut.shtml vertices = 1000 t = from 0 to (2*PI) r = 10 n = rand2(0.1, 10) p = r*pow(sin(t), n) x = p*cos(t) y = p*sin(t)
面:
vertices = D1:512 D2:200 u = from 0 to (2*PI) D1 v = from 0 to 50 D2 r = 10 p = r*pow(abs(sin(u)), v) x = p*cos(u) y = p*sin(u)