思路:
a+b problem
Tip:
无
#include <bits/stdc++.h> using namespace std; int main() { int a, b, c; cin >> a >> b >> c; cout << a - b * c << endl; return 0; }
思路:
a+b problem
Tip:
无
#include <bits/stdc++.h> using namespace std; int main() { int a, b, c; cin >> a >> b >> c; cout << a - b * c << endl; return 0; }