Sicily 1681: Matchsticks（贪心）

　　题意：给出n根火柴，求其能拼成的最小正整数和最大正整数。求最大正整数时，尽量让位数多一点，而数字“1”消耗的火柴数最少，所以尽量尽量用“1”，求最小正整数时，尽量让位数少一点，而数字“8”消耗的火柴数最少，所以尽量用“8”，不过有许多特殊情况需要判断：

#include<bits/stdc++.h>
using namespace std;

string MIN(int n){
    string s = "";
    while(n){
        if(n == 17){
            s = "200"+s;
            n -= 17;
        } 
        else if(n == 11){
            s ="20" + s;
            n -= 11;
        }
        else if(n == 10){
            s = "22" + s;
            n -= 10;
        }
        else if(n >= 9 || n == 7){
            s = "8" + s;
            n -= 7; 
        } 
        else if(n == 8){
            s = "0"+s;
            n -= 6;
        }
        else if(n == 6){
//            if(s == "")s = "0";//一开始以为6的时候是0.被坑惨了，好好读题！
//            else s = "6" + s;
            s = "6" + s;
            n -= 6; 
        } 
        else if(n == 5){
            s = "2"+s;
            n -= 5;
        }
        else if(n == 4){
            s = "4" + s;
            n -= 4;
        }
        else if(n == 3){
            s = "7" + s;
            n -= 3;
        }
        else if(n == 2){
            s = "1" + s;
            n -= 2;
        }
    }
    return s;
}
string MAX(int n){
    string s = "";
    while(n > 3){
        s = "1" + s;
        n -= 2;
    }
    if(n == 3)return "7"+s;
    else if(n == 2)return "1"+s;
}

int main(){
    int n;
    cin >> n;
    for(int i = 0; i < n; i++){
        int num;
        cin >> num;
        cout << MIN(num) << ' ' << MAX(num) << endl;
    }
//    for(int i = 2; i < 101; i++){//可以把数字都打出来看看
//        cout << i << ' ' << MIN(i) << ' ' << MAX(i) << endl; 
//    }
}