Given preorder and inorder traversal of a tree, construct the binary tree.
Note:
You may assume that duplicates do not exist in the tree.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: template<typename Iter> void creatTree(TreeNode *&root, Iter preBeg,Iter preEnd,Iter inBeg,Iter inEnd) { if (preBeg==preEnd||inBeg==inEnd) { root=NULL; return; } root=new TreeNode(*preBeg); vector<int>::iterator tmp=find(inBeg,inEnd,*preBeg); int leftsize=tmp-inBeg; creatTree(root->left, preBeg+1,preBeg+leftsize+1,inBeg,tmp); creatTree(root->right, preBeg+leftsize+1,preEnd,tmp+1,inEnd); } TreeNode *buildTree(vector<int> &preorder, vector<int> &inorder) { TreeNode *root; creatTree(root,preorder.begin(),preorder.end(),inorder.begin(),inorder.end()); return root; } /* TreeNode * creatTree(vector<int>::iterator preBeg,vector<int>::iterator preEnd,vector<int>::iterator inBeg,vector<int>::iterator inEnd) { if (preBeg==preEnd||inBeg==inEnd) { return NULL; } TreeNode *root=new TreeNode(*preBeg); vector<int>::iterator tmp=find(inBeg,inEnd,*preBeg); int leftsize=tmp-inBeg; root->left=creatTree(preBeg+1,preBeg+leftsize+1,inBeg,tmp); root->right=creatTree(preBeg+leftsize+1,preEnd,tmp+1,inEnd); return root; } TreeNode *buildTree(vector<int> &preorder, vector<int> &inorder) { return creatTree(preorder.begin(),preorder.end(),inorder.begin(),inorder.end()); } */ };