Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example:
Given the below binary tree and sum = 22
,
5 / 4 8 / / 11 13 4 / / 7 2 5 1
return
[ [5,4,11,2], [5,8,4,5] ]
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: void find(vector<vector<int>> &res, vector<int> tmp, TreeNode *root,int sum) { if(root==NULL)return; if(root->left==NULL&&root->right==NULL) { if(root->val==sum) { tmp.push_back(root->val); res.push_back(tmp); } return; } tmp.push_back(root->val); find(res,tmp,root->left,sum-root->val); find(res,tmp,root->right,sum-root->val); } vector<vector<int> > pathSum(TreeNode *root, int sum) { vector<vector<int>> res; vector<int> tmp; find(res,tmp,root,sum); return res; } };