• POJ 3308 最少点集覆盖


    题意:和Uva 11419 类似。

    首先最少点集覆盖 = 最大匹配。

    我们可以在 S 和行 的边 不是1,有了权值,但是题意要求的是乘积最小,那么可以用 log(a*b) = loga + logb 转换,那么权值就是logr ,logc;

    最大匹配 = 最大流(最大流一定经过最小割,最小割=最大流)。那么题目就转换为求最大流了。

    但是,这个题目很流氓,vector的邻接表超时,数组模拟的G++ WA,C++ AC.

    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <vector>
    #include <queue>
    #include <cmath>
    
    using namespace std;
    
    /*
    const double inf = 1000000.0;
    const int maxn = 100;
    int dblcmp(double d) {
        if(fabs(d)<1e-5)
            return 1;
        return 0;
    }
    
    struct Edge {
        int from,to;
        double cap,flow;
    };
    
    struct Dinic
    {
        int n,m,s,t;
        vector<Edge> edge;
        vector<int> G[maxn];
        bool vis[maxn];
        int d[maxn];
        int cur[maxn];
    
        void init()
        {
            for(int i=0;i<maxn;i++)
                G[i].clear();
            edge.clear();
            memset(d,0,sizeof(d));
            memset(vis,0,sizeof(vis));
            memset(cur,0,sizeof(cur));
        }
    
        void AddEdge (int from,int to,double cap)
        {
            edge.push_back((Edge){from,to,cap,0});
            edge.push_back((Edge){to,from,0,0});
            m = edge.size();
            G[from].push_back(m-2);
            G[to].push_back(m-1);
        }
    
        bool BFS()
        {
            memset(vis,0,sizeof(vis));
            queue<int> Q;
            Q.push(s);
            d[s] = 0;
            vis[s] = 1;
            while(!Q.empty())
            {
                int x = Q.front();
                Q.pop();
                for(int i=0; i<G[x].size(); i++)
                {
                    Edge & e = edge[G[x][i]];
                    if(!vis[e.to]&&e.cap>e.flow)
                    {
                        vis[e.to] = 1;
                        d[e.to] = d[x] + 1;
                        Q.push(e.to);
                    }
                }
            }
            return vis[t];
        }
    
        double DFS(int x,double a)
        {
            if(x==t||dblcmp(a)) return a;
            double flow = 0,f;
            for(int & i = cur[x]; i<G[x].size(); i++)
            {
                Edge & e = edge[G[x][i]];
                if(d[x] + 1==d[e.to]&&(f=DFS(e.to,min(a,e.cap-e.flow)))>0)
                {
                    e.flow +=f;
                    edge[G[x][i]^1].flow -=f;
                    flow +=f;
                    a-=f;
                    if(dblcmp(a)) break;
                }
            }
            return flow;
        }
    
        double Maxflow (int s,int t) {
            this->s = s;this->t = t;
            double flow = 0;
            while(BFS()) {
                memset(cur,0,sizeof(cur));
                flow+=DFS(s,inf);
            }
            return flow;
        }
    
    }sol;
    */
    
    const int N = 105;
    const double inf = 1000000.0;
    
    struct Edge{
        int s,e,next;
        double v;
    }edge[15*N];
    
    int n,e_num,head[N],d[N],sp,tp;
    
    void AddEdge(int a,int b,double c){
        edge[e_num].s=a; edge[e_num].e=b; edge[e_num].v=c;
        edge[e_num].next=head[a]; head[a]=e_num++;
    
        edge[e_num].s=b; edge[e_num].e=a; edge[e_num].v=0.0;
        edge[e_num].next=head[b]; head[b]=e_num++;
    }
    
    int bfs(){
        queue <int> q;
        memset(d,-1,sizeof(d));
        d[sp]=0;
        q.push(sp);
        while(!q.empty()){
            int cur=q.front();
            q.pop();
            for(int i=head[cur];i!=-1;i=edge[i].next){
                int u=edge[i].e;
                if(d[u]==-1 && edge[i].v>0){//没有标记,且可行流大于0
                    d[u]=d[cur]+1;
                    q.push(u);
                }
            }
        }
        return d[tp] != -1;//汇点是否成功标号,也就是说是否找到增广路
    }
    
    double dfs(int a,double b){//a为起点
        double r=0;
        if(a==tp)return b;
        for(int i=head[a];i!=-1 && r<b;i=edge[i].next){
            int u=edge[i].e;
            if(edge[i].v>0 && d[u]==d[a]+1){
                double x=min(edge[i].v,b-r);
                x=dfs(u,x);
                r+=x;
                edge[i].v-=x;
                edge[i^1].v+=x;
            }
        }
        if(!r)d[a]=-2;
        return r;
    }
    
    double dinic(int sp,int tp){
        double total=0.0,t;
        while(bfs()){
            while(t=dfs(sp,inf))
            total+=t;
        }
        return total;
    }
    
    int main()
    {
        int t;
        scanf("%d",&t);
        int i,m,l,a,b;
        double row[N],col[N];
        while(t--) {
    
            /*
            //sol.init();
            int m,n,l;
            scanf("%d%d%d",&m,&n,&l);
            sp = 0,tp=m+n+1;
            e_num=0;
            memset(head,-1,sizeof(head));
            for(int i=1;i<=m;i++) {
                double r;
                scanf("%lf",&r);
                //sol.AddEdge(s,i,log(r));
                AddEdge(sp,i,log(r));
            }
    
            for(int i=1;i<=n;i++) {
                double c;
                scanf("%lf",&c);
                //sol.AddEdge(i+m,t,log(c));
                AddEdge(i+m,tp,log(c));
            }
    
            for(int i=0;i<l;i++) {
                int u,v;
                scanf("%d%d",&u,&v);
                v+=m;
                //sol.AddEdge(u,v,inf);
                AddEdge(u,v,inf);
            }
    
            //double ans = sol.Maxflow(s,t);
            double ans = dinic(sp,tp);
            printf("%.4lf
    ",exp(ans));
            */
    
            scanf("%d%d%d",&n,&m,&l);
            for(i=1;i<=n;i++)
                scanf("%lf",&row[i]);
            for(i=1;i<=m;i++)
                scanf("%lf",&col[i]);
    
            e_num=0;
            memset(head,-1,sizeof(head));
            sp=0; tp=n+m+1;
            for(i=1;i<=n;i++)
                AddEdge(sp,i,log(row[i]));
            for(i=1;i<=m;i++)
                AddEdge(n+i,tp,log(col[i]));
            for(i=1;i<=l;i++){
                scanf("%d%d",&a,&b);
                AddEdge(a,n+b,inf);
            }
    
            printf("%.4lf
    ",exp(dinic(sp,tp)));
    
        }
    
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/TreeDream/p/7204101.html
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