字符串处理,Poj(2121)

题目链接：http://poj.org/problem?id=2121

差一点就WA哭了，主要是自己傻逼了。

思路：

遇到hundred，sum*100;

但是遇到thouthend,million,ans+=sum*(... ...),sum=0;

因为到了thouthend,million，后面肯定又是新的数字，跟前面的没关系了，sum=0;

而hundred,后面是可以再加数的，比如22，所以这里只要sum*=100;

注意：

这里经典的一招，杰哥教我的，要重置一下order,只需要order[k]='/0';

而不需要memset了。

#include <stdio.h>
#include <iostream>
#include <string.h>

using namespace std;

char str[200];

int main()
{
    while(gets(str))
    {
        //printf("%s",str);
        if(strcmp(str,"")==0)
            break;
        bool flag = false;
        int ans=0;
        int sum=0;
        char order[30]={''};
        int k=0;
        for(int i=0;i<strlen(str)+1;i++)
        {
            if(str[i]!=' '&&str[i]!='')
                order[k++] = str[i];
            else{
                order[k] = '';
                k=0;
                if(!strcmp(order,"negative")) flag = true;
                if(!strcmp(order,"zero")) sum+=0;
                if(!strcmp(order,"one")) sum+=1;
                if(!strcmp(order,"two")) sum+=2;
                if(!strcmp(order,"three")) sum+=3;
                if(!strcmp(order,"four")) sum+=4;
                if(!strcmp(order,"five")) sum+=5;
                if(!strcmp(order,"six")) sum+=6;
                if(!strcmp(order,"seven")) sum+=7;
                if(!strcmp(order,"eight")) sum+=8;
                if(!strcmp(order,"nine")) sum+=9;
                if(!strcmp(order,"ten")) sum+=10;
                if(!strcmp(order,"eleven")) sum+=11;
                if(!strcmp(order,"twelve")) sum+=12;
                if(!strcmp(order,"thirteen")) sum+=13;
                if(!strcmp(order,"fourteen")) sum+=14;
                if(!strcmp(order,"fifteen")) sum+=15;
                if(!strcmp(order,"sixteen")) sum+=16;
                if(!strcmp(order,"seventeen")) sum+=17;
                if(!strcmp(order,"eighteen")) sum+=18;
                if(!strcmp(order,"nineteen")) sum+=19;
                if(!strcmp(order,"twenty")) sum+=20;
                if(!strcmp(order,"thirty")) sum+=30;
                if(!strcmp(order,"forty")) sum+=40;
                if(!strcmp(order,"fifty")) sum+=50;
                if(!strcmp(order,"sixty")) sum+=60;
                if(!strcmp(order,"seventy")) sum+=70;
                if(!strcmp(order,"eighty")) sum+=80;
                if(!strcmp(order,"ninety")) sum+=90;
                if(!strcmp(order,"hundred"))
                {
                    sum=sum*100;
                }
                if(!strcmp(order,"thousand"))
                {
                    ans = ans+sum * 1000;
                    sum = 0;
                }
                if(!strcmp(order,"million"))
                {
                    ans =ans+sum *1000000;
                    sum = 0;
                }
            }
        }


        if(flag)
            printf("-%d
",ans+sum);
        else printf("%d
",ans+sum);
    }
    return 0;
}