• Something


    ahhhh...终于处理完基础数论了...码了少量代码...

    1 int GCD(int a,int b)
    2 {
    3     return !b?a:GCD(b,a%b);
    4 }
    GCD
    void exgcd(int a,int b,int &x,int &y)
    {
        if(b==0)
        {
            x=1,y=0;return;
        }
        exgcd(b,a%b,x,y);
        int t=x;x=y;y=t-a/b*y;
    }
    exgcd
    1 int GCD(int a,int b)
    2 {
    3     return !b?a:GCD(b,a%b);
    4 }
    5 int lcm(int a,int b)
    6 {
    7     return a*b/GCD(a,b);
    8 }
    lcm
     1 int FastPower(int Tp,int Up,int mod)
     2 {
     3     int r=1,base=Tp;
     4     while(b)
     5     {
     6         if(b&1)
     7             r*=base;
     8         base*=base;
     9         b>>1;
    10     }
    11     return r;
    12 }
    FastPower
     1 int prime[1100000],primesize,phi[11000000];
     2 bool isprime[11000000];
     3 void getlist(int listsize)
     4 {
     5     memset(isprime,1,sizeof(isprime));
     6     isprime[1]=false;
     7     for(int i=2;i<=listsize;i++)
     8     {
     9         if(isprime[i])prime[++primesize]=i;
    10          for(int j=1;j<=primesize&&i*prime[j]<=listsize;j++)
    11          {
    12             isprime[i*prime[j]]=false;
    13             if(i%prime[j]==0)break;
    14         }
    15     }
    16 }
    LinearPrime
     1 int getphi(int x){
     2     int ret=1;
     3     for(int i=1;prime[i]*prime[i]<=x;i++){
     4         if(x%prime[i]==0){
     5             ret*=prime[i]-1;x/=prime[i];
     6             while(x%prime[i]==0) x/=prime[i],ret*=prime[i];
     7         }
     8     }
     9     if(x>1) ret*=x-1;
    10     return ret;
    11 }
    phi

    待填的坑:

    BSGS.

    More Template(Packaged)...

     1 #define N 1000000
     2 struct SPFA
     3 {
     4     queue<int> q;
     5     bool vis[N];
     6     int dis[N];
     7     SPFA()
     8     {
     9         memset(vis,0,sizeof(vis));
    10         memset(dis,0,sizeof(dis));
    11     }
    12     void spfa(int p)
    13     {
    14         q.push(p);
    15         vis[p]=true;
    16         while(!q.empty())
    17         {
    18             int t=q.front();
    19             q.pop();
    20             vis[t]=false;
    21             for(int i=1; i<=n; i++)
    22             {
    23                 if(dis[i]>dis[t]+map[t][i])
    24                 {
    25                     dis[i]=dis[t]+map[t][i];
    26                     if(!vis[i])
    27                         q.push(i);
    28                 }
    29             }
    30         }
    31         printf("%d",dis[ep]);
    32     }
    33 };
    spfa
     1 struct BIT{
     2     long long c[N];
     3     int n;
     4     BIT()
     5     {
     6         memset(c,0,sizeof(c));
     7         n=0;
     8     }
     9 
    10     int lowbit(int x)
    11     {
    12         return x&(-x);
    13     }
    14     void modify(int x,long long y)
    15     {
    16         for(;x<=n;x+=lowbit(x))
    17             c[x]+=y;
    18     }
    19     long long query(int x)
    20     {
    21         long long ret=0;
    22         for(;x;x-=lowbit(x))
    23             ret+=c[x];
    24         return ret;
    25     }
    26     long long query(int l,int r)
    27     {
    28         return query(r)-query(l-1);
    29     }
    30 };
    bit
     1 #define Maxn 1000000
     2 #define Maxm 1000
     3 struct KMP{
     4     int pre[Maxn];
     5     int len1,len2;
     6     int p;
     7 
     8     KMP()
     9     {
    10         for(int i=0;i<Maxn;i++)
    11             pre[i]=0;
    12     }
    13 
    14     inline void preprocess(char*pattern)
    15     {
    16         len2=strlen(pattern),p=-1;
    17         pre[0]=-1;
    18         for(int i=1;i<len2;i++)
    19         {
    20             while(p!=-1&&pattern[p+1]!=pattern[i])
    21                 p=pre[p];
    22             p+=(pattern[p+1]==pattern[i]);
    23             pre[i]=p;
    24         }
    25     }
    26 
    27     inline void kmp(char*original,char*pattern)
    28     {
    29         len1=strlen(original);
    30         p=-1;
    31         for(int i=0;i<len1;i++)
    32         {
    33             while(p!=-1&&original[i]!=pattern[p+1])
    34                 p=pre[p];
    35             p+=(pattern[p+1]==original[i]);
    36             if(p+1==len2)
    37                 printf("%d
    ",i-len2+2),p=pre[p];
    38         }
    39         for(int i=0;i<len2;i++)
    40             printf("%d ",pre[i]+1);
    41     }
    42 };
    kmp
     1 struct SegmentTreeTypeAdd
     2 {
     3     struct node
     4     {
     5         int l,r,w,f;//left,right,weight,flag;
     6         node()
     7         {
     8             l=r=w=f=0;
     9         }
    10     } tree[400001];
    11     inline void build(int k,int ll,int rr)//建树
    12     {
    13         //用法:build(节点编号,左孩子,右孩子);
    14         //初始化:build(1,1,节点个数);
    15         tree[k].l=ll,tree[k].r=rr;
    16         if(tree[k].l==tree[k].r)
    17         {
    18             scanf("%d",&tree[k].w);
    19             return;
    20         }
    21         int m=(ll+rr)/2;
    22         build(k*2,ll,m);
    23         build(k*2+1,m+1,rr);
    24         tree[k].w=tree[k*2].w+tree[k*2+1].w;
    25     }
    26     inline void down(int k)//标记下传
    27     {
    28         //用法:down(需要下传标记的根节点);
    29         tree[k*2].f+=tree[k].f;
    30         tree[k*2+1].f+=tree[k].f;
    31         tree[k*2].w+=tree[k].f*(tree[k*2].r-tree[k*2].l+1);
    32         tree[k*2+1].w+=tree[k].f*(tree[k*2+1].r-tree[k*2+1].l+1);
    33         tree[k].f=0;
    34     }
    35     inline void ask_point(int k)//单点查询
    36     {
    37         //用法:ask_point(需要查询的点的编号);
    38         if(tree[k].l==tree[k].r)
    39         {
    40             ans=tree[k].w;
    41             return ;
    42         }
    43         if(tree[k].f) down(k);
    44         int m=(tree[k].l+tree[k].r)/2;
    45         if(x<=m) ask_point(k*2);
    46         else ask_point(k*2+1);
    47     }
    48     inline void change_point(int k)//单点修改
    49     {
    50         //用法:change_point(需要修改的点的编号);
    51         if(tree[k].l==tree[k].r)
    52         {
    53             tree[k].w+=y;
    54             return;
    55         }
    56         int m=(tree[k].l+tree[k].r)/2;
    57         if(x<=m) change_point(k*2);
    58         else change_point(k*2+1);
    59         tree[k].w=tree[k*2].w+tree[k*2+1].w;
    60     }
    61     inline void ask_interval(int k)//区间查询
    62     {
    63         //用法:ask_iterval(查询起点);
    64         if(tree[k].l>=a&&tree[k].r<=b)//a与b为需要查询的区间
    65         {
    66             ans+=tree[k].w;
    67             return;
    68         }
    69         if(tree[k].f) down(k);
    70         int m=(tree[k].l+tree[k].r)/2;
    71         if(a<=m) ask_interval(k*2);
    72         if(b>m) ask_interval(k*2+1);
    73     }
    74     inline void change_interval(int k)//区间修改
    75     {
    76         //用法:change_interval(修改起点);
    77         if(tree[k].l>=a&&tree[k].r<=b)//a与b为需要修改的区间
    78         {
    79             tree[k].w+=(tree[k].r-tree[k].l+1)*y;
    80             tree[k].f+=y;
    81             return;
    82         }
    83         if(tree[k].f) down(k);//若有孩子节点,下传标记
    84         int m=(tree[k].l+tree[k].r)/2;//二分处理
    85         if(a<=m) change_interval(k*2);
    86         if(b>m) change_interval(k*2+1);
    87         tree[k].w=tree[k*2].w+tree[k*2+1].w;
    88     }
    89 };
    SegmentTree
     1 #define N 1000000
     2 struct Graph
     3 {
     4     struct node
     5     {
     6         int next,to,dis;
     7     } edge[N];
     8     int head[N];
     9     void add(int u,int v,int w)
    10     {
    11         edge[++cnt].next=head[u];
    12         edge[cnt].to=v;
    13         edge[cnt].dis=w;
    14         head[u]=cnt;
    15     }
    16 };
    17 Graph g;
    18 struct Dijkstra
    19 {
    20     struct NODE
    21     {
    22         int x,y;
    23         bool operator < (NODE a)const
    24         {
    25             return x>a.x;
    26         }
    27     };
    28     priority_queue<NODE>q;
    29     int cnt,n,m,s,t,dis[N/2];
    30     bool visit[N/2];
    31     void dijkstra()
    32     {
    33         memset(dis,1,sizeof(dis));
    34         dis[s]=0;
    35         NODE a;
    36         a.x=dis[s];
    37         a.y=s;
    38         q.push(a);
    39         while(!q.empty())
    40         {
    41             NODE a=q.top();
    42             q.pop();
    43             if(visit[a.x]) continue;
    44             int v=a.y;
    45             visit[v]=1;
    46             for(int i=g.head[v]; i; i=g.edge[i].next)
    47             {
    48                 if(dis[g.edge[i].to]>g.edge[i].dis+dis[v])
    49                 {
    50                     dis[g.edge[i].to]=g.edge[i].dis+dis[v];
    51                     NODE a;
    52                     a.x=dis[g.edge[i].to];
    53                     a.y=g.edge[i].to;
    54                     q.push(a);
    55                 }
    56             }
    57         }
    58         printf("%d",dis[t]);
    59     }
    60 };
    dijkstra(heap optimized)
     1 #define N 1000000
     2 struct Graph
     3 {
     4     struct node
     5     {
     6         int next,to,dis;
     7     } edge[N<<1];
     8     int head[N/2];
     9     void add(int u,int v,int w)
    10     {
    11         edge[++cnt].next=head[u];
    12         edge[cnt].to=v;
    13         edge[cnt].dis=w;
    14         head[u]=cnt;
    15     }
    16 };
    graph
     1 #define maxn 10005
     2 struct UnionFindSet
     3 {
     4     int x,y,v;
     5     int fat[maxn];
     6     UnionFindSet()
     7     {
     8         for(int i=0; i<maxn; i++)
     9             fat[i]=i;
    10     }
    11     inline int father(int x)
    12     {
    13         if(fat[x]!=x)
    14             fat[x]=father(fat[x]);
    15         return fat[x];
    16     }
    17     inline void unionn(int x,int y)
    18     {
    19         int fa=father(x);
    20         int fb=father(y);
    21         if(fa!=fb)
    22             fat[fa]=fb;
    23     }
    24 };
    25 struct Edge
    26 {
    27     int pre,to,w;
    28     bool operator < (const Edge &b) const
    29     {
    30         return this->w < b.w;
    31     }
    32 };
    33 struct Graph
    34 {
    35     Edge edge[maxn];
    36     int cnt=0;
    37     inline void AddEdge(int u,int v,int w)
    38     {
    39         edge[++cnt].pre=u;
    40         edge[cnt].to=v;
    41         edge[cnt].w=w;
    42     }
    43 };
    44 Graph g;
    45 UnionFindSet s;
    46 int Kruskal(int EdgeNumber)
    47 {
    48     sort(g.edge+1,g.edge+1+EdgeNumber);
    49     int n=1,ans=0;
    50     while(n<EdgeNumber-1)
    51     {
    52         if(s.father(g.edge[n].pre)!=s.father(g.edge[n].to))
    53         {
    54             s.unionn(g.edge[n].pre,g.edge[n].to);
    55             ans+=g.edge[n].w;
    56         }
    57         n++;
    58     }
    59     return ans;
    60 }
    kruskal
     1 #define maxn 10005
     2 struct UnionFindSet
     3 {
     4     int x,y,v;
     5     int fat[maxn];
     6     UnionFindSet()
     7     {
     8         for(int i=0; i<maxn; i++)
     9             fat[i]=i;
    10     }
    11     inline int father(int x)
    12     {
    13         if(fat[x]!=x)
    14             fat[x]=father(fat[x]);
    15         return fat[x];
    16     }
    17     inline void unionn(int x,int y)
    18     {
    19         int fa=father(x);
    20         int fb=father(y);
    21         if(fa!=fb)
    22             fat[fa]=fb;
    23     }
    24 };
    UnionFindSet

     hhhh...上面的板子编译都不一定过...得手调一下...

    下面是splay&&treap&&dinic板子...编译过了...

      1 #include<cstdio>
      2 #define N 100010
      3 using namespace std;
      4 int root,nn,n,tot;
      5 class SPLAY
      6 {
      7     private:
      8         int fa[N],ch[N][2],siz[N],cnt[N];
      9         
     10         int son(int x)
     11         {
     12             return x==ch[fa[x]][1];
     13         }
     14 
     15         void pushup(int rt)
     16         {
     17             int l=ch[rt][0],r=ch[rt][1];
     18             siz[rt]=siz[l]+siz[r]+cnt[rt];
     19         }
     20 
     21         void rotate(int x)
     22         {
     23             int y=fa[x],z=fa[y],b=son(x),c=son(y),a=ch[x][!b];
     24             if(z) ch[z][c]=x;
     25             else root=x;
     26             fa[x]=z;
     27             if(a) fa[a]=y;
     28             ch[y][b]=a;
     29             ch[x][!b]=y;
     30             fa[y]=x;
     31             pushup(y);
     32             pushup(x);
     33         }
     34 
     35         void splay(int x,int i)
     36         {
     37             while(fa[x]!=i)
     38             {
     39                 int y=fa[x],z=fa[y];
     40                 if(z==i)
     41                 {
     42                     rotate(x);
     43                 }
     44                 else
     45                 {
     46                     if(son(x)==son(y))
     47                     {
     48                         rotate(y);
     49                         rotate(x);
     50                     }
     51                     else
     52                     {
     53                         rotate(x);
     54                         rotate(x);
     55                     }
     56                 }
     57             }
     58         }
     59     public:
     60         int data[N];
     61         void ins(int &rt,int x)
     62         {
     63             if(rt==0)
     64             {
     65                 rt=++nn;
     66                 data[nn]=x;
     67                 siz[nn]=cnt[nn]=1;
     68                 return;
     69             }
     70             if(x==data[rt])
     71             {
     72                 cnt[rt]++;
     73                 siz[rt]++;
     74                 return;
     75             }
     76             if(x<data[rt])
     77             {
     78                 ins(ch[rt][0],x);
     79                 fa[ch[rt][0]]=rt;
     80                 pushup(rt);
     81             }
     82             else
     83             {
     84                 ins(ch[rt][1],x);
     85                 fa[ch[rt][1]]=rt;
     86                 pushup(rt);
     87             }
     88         }
     89 
     90         int getpre(int rt,int x)
     91         {
     92             int p=rt,ans;
     93             while(p)
     94             {
     95                 if(x<=data[p])
     96                 {
     97                     p=ch[p][0];
     98                 }
     99                 else
    100                 {
    101                     ans=p;
    102                     p=ch[p][1];
    103                 }
    104             }
    105             return ans;
    106         }
    107 
    108         int getsuc(int rt,int x)
    109         {
    110             int p=rt,ans;
    111             while(p)
    112             {
    113                 if(x>=data[p])
    114                 {
    115                     p=ch[p][1];
    116                 }
    117                 else
    118                 {
    119                     ans=p;
    120                     p=ch[p][0];
    121                 }
    122             }
    123             return ans;
    124         }
    125 
    126         int getmn(int rt)
    127         {
    128             int p=rt,ans=-1;
    129             while(p)
    130             {
    131                 ans=p;
    132                 p=ch[p][0];
    133             }
    134             return ans;
    135         }
    136 
    137         void del(int rt,int x)
    138         {
    139             if(data[rt]==x)
    140             {
    141                 if(cnt[rt]>1)
    142                 {
    143                     cnt[rt]--;
    144                     siz[rt]--;
    145                 }
    146                 else
    147                 {
    148                     splay(rt,0);
    149                     int p=getmn(ch[rt][1]);
    150                     if(p!=-1)
    151                     {
    152                         splay(p,rt);
    153                         root=p;
    154                         fa[p]=0;
    155                         ch[p][0]=ch[rt][0];
    156                         fa[ch[rt][0]]=p;
    157                         pushup(p);
    158                     }
    159                     else
    160                     {
    161                         root=ch[rt][0];
    162                         fa[ch[rt][0]]=0;
    163                     }
    164                 }
    165                 return;
    166             }
    167             if(x<data[rt])
    168             {
    169                 del(ch[rt][0],x);
    170                 pushup(rt);
    171             }
    172             else
    173             {
    174                 del(ch[rt][1],x);
    175                 pushup(rt);
    176             }
    177         }
    178 
    179         int getk(int rt,int k)
    180         {
    181             if(data[rt]==k)
    182             {
    183                 splay(rt,0);
    184                 if(ch[rt][0]==0)
    185                 {
    186                     return 1;
    187                 }
    188                 else
    189                 {
    190                     return siz[ch[rt][0]]+1;
    191                 }
    192             }
    193             if(k<data[rt]) return getk(ch[rt][0],k);
    194             else return getk(ch[rt][1],k);
    195         }
    196 
    197         int getkth(int rt,int k)
    198         {
    199             int l=ch[rt][0];
    200             if(siz[l]+1<=k&&k<=siz[l]+cnt[rt]) return data[rt];
    201             if(k<siz[l]+1) return getkth(ch[rt][0],k);
    202             if(siz[l]+cnt[rt]<k) return getkth(ch[rt][1],k-(siz[l]+cnt[rt]));
    203         }
    204 };
    205 
    206 SPLAY s;
    207 int main()
    208 {
    209     scanf("%d",&n);
    210     while(n--)
    211     {
    212         int opt,x;
    213         scanf("%d%d",&opt,&x);
    214         if(opt==1)
    215         {
    216             tot++;
    217             s.ins(root,x);
    218         }
    219         if(opt==2)
    220         {
    221             tot--;
    222             s.del(root,x);
    223         }
    224         if(opt==3)
    225         {
    226             printf("%d
    ",s.getk(root,x));
    227         }
    228         if(opt==4)
    229         {
    230             printf("%d
    ",s.getkth(root,x));
    231         }
    232         if(opt==5)
    233         {
    234             printf("%d
    ",s.data[s.getpre(root,x)]);
    235         }
    236         if(opt==6)
    237         {
    238             printf("%d
    ",s.data[s.getsuc(root,x)]);
    239         }
    240     }
    241     return 0;
    242 }
    splay
      1 #include<cstdio>
      2 #include<algorithm>
      3 #define N 100010
      4 using namespace std;
      5 
      6 struct TreapType
      7 {
      8     TreapType *l,*r;
      9     int key,fix,size;
     10     TreapType(int _key):fix(rand()),key(_key),l(NULL),r(NULL),size(1) {}
     11     inline void update()
     12     {
     13         size=1+(l?l->size:0)+(r?r->size:0);
     14     }
     15 }*root;
     16 
     17 int T;
     18 
     19 typedef pair<TreapType*,TreapType*> Droot;
     20 
     21 inline int Size(TreapType *x)
     22 {
     23     return x?x->size:0;
     24 }
     25 
     26 Droot Split(TreapType *x,int k)
     27 {
     28     if(!x) return Droot(NULL,NULL);
     29     Droot y;
     30     if(Size(x->l)>=k)
     31     {
     32         y=Split(x->l,k);
     33         x->l=y.second;
     34         x->update();
     35         y.second=x;
     36     }
     37     else
     38     {
     39         y=Split(x->r,k-Size(x->l)-1);
     40         x->r=y.first;
     41         x->update();
     42         y.first=x;
     43     }
     44     return y;
     45 }
     46 
     47 TreapType* Merge(TreapType *A,TreapType *B)
     48 {
     49     if(!A) return B;
     50     if(!B) return A;
     51     if(A->fix<B->fix)
     52     {
     53         A->r=Merge(A->r,B);
     54         A->update();
     55         return A;
     56     }
     57     else
     58     {
     59         B->l=Merge(A,B->l);
     60         B->update();
     61         return B;
     62     }
     63 }
     64 
     65 int Getkth(TreapType *x,int k)
     66 {
     67     if(!x) return 0;
     68     return k<=x->key?Getkth(x->l,k):Getkth(x->r,k)+Size(x->l)+1;
     69 }
     70 
     71 int Findkth(int k)
     72 {
     73     Droot x=Split(root,k-1);
     74     Droot y=Split(x.second,1);
     75     TreapType *ans=y.first;
     76     root=Merge(Merge(x.first,ans),y.second);
     77     return ans->key;
     78 }
     79 
     80 void Insert(int v)
     81 {
     82     int k=Getkth(root,v);
     83     Droot x=Split(root,k);
     84     TreapType *now=new TreapType(v);
     85     root=Merge(Merge(x.first,now),x.second);
     86 }
     87 
     88 void Delete(int v)
     89 {
     90     int k=Getkth(root,v);
     91     Droot x=Split(root,k);
     92     Droot y=Split(x.second,1);
     93     root=Merge(x.first,y.second);
     94 }
     95 
     96 int Pre(int v)
     97 {
     98     int k=Getkth(root,v);
     99     Droot x=Split(root,k-1);
    100     Droot y=Split(x.second,1);
    101     TreapType *ans=y.first;
    102     root=Merge(Merge(x.first,ans),y.second);
    103     return ans->key;
    104 }
    105 
    106 int Suc(int v)
    107 {
    108     int k=Getkth(root,v+1);
    109     Droot x=Split(root,k);
    110     Droot y=Split(x.second,1);
    111     TreapType *ans=y.first;
    112     root=Merge(Merge(x.first,ans),y.second);
    113     return ans->key;
    114 }
    115 
    116 int main()
    117 {
    118     scanf("%d",&T);
    119     while(T--)
    120     {
    121         int opt,x;
    122         scanf("%d%d",&opt,&x);
    123         if(opt==1)
    124         {
    125             Insert(x);
    126         }
    127         if(opt==2)
    128         {
    129             Delete(x);
    130         }
    131         if(opt==3)
    132         {
    133             printf("%d
    ",Getkth(root,x)+1);
    134         }
    135         if(opt==4)
    136         {
    137             printf("%d
    ",Findkth(x));
    138         }
    139         if(opt==5)
    140         {
    141             printf("%d
    ",Pre(x));
    142         }
    143         if(opt==6)
    144         {
    145             printf("%d
    ",Suc(x));
    146         }
    147     }
    148     return 0;
    149 }
    treap
     1 #include<cstdio>
     2 #include<cstring>
     3 #include<algorithm>
     4 using namespace std;
     5 #define N 1000000
     6 #define inf 0x3f3f3f3f
     7 struct Graph
     8 {
     9     struct node
    10     {
    11         int next,to,dis;
    12     } edge[N<<1];
    13     int head[N/2],cnt;
    14     Graph(){cnt=1;}
    15     void add(int u,int v,int w)
    16     {
    17         edge[++cnt].next=head[u];
    18         edge[cnt].to=v;
    19         edge[cnt].dis=w;
    20         head[u]=cnt;
    21     }
    22 };
    23 Graph g;
    24 class Dinic
    25 {
    26     private:
    27         int q[N<<1],h[N<<1],ans,n,S,T;
    28         inline void insert(int u,int v,int f)
    29         {
    30             g.add(u,v,f);
    31             g.add(v,u,0);
    32         }
    33 
    34         bool bfs()
    35         {
    36             int t=0,w=1;
    37             memset(h,-1,sizeof(h));
    38             q[t]=S;
    39             h[S]=0;
    40             while(t<w)
    41             {
    42                 int now=q[t++];
    43                 for(int i=g.head[now]; i; i=g.edge[i].next)
    44                 {
    45                     int v=g.edge[i].to;
    46                     if(h[v]==-1&&g.edge[i].to)
    47                     {
    48                         h[v]=h[now]+1;
    49                         q[w++]=v;
    50                     }
    51                 }
    52             }
    53             if(h[T]!=-1) return 1;
    54             return 0;
    55         }
    56 
    57         int dfs(int x,int f)
    58         {
    59             if(x==T) return f;
    60             int w,used=0;
    61             for(int i=g.head[x]; i; i=g.edge[i].next)
    62             {
    63                 int v=g.edge[i].to;
    64                 if(h[v]==h[x]+1)
    65                 {
    66                     w=dfs(v,min(f-used,g.edge[i].to));
    67                     g.edge[i].to-=w;
    68                     g.edge[i^1].to+=w;
    69                     used+=w;
    70                     if(used==f) return f;
    71                 }
    72 
    73             }
    74             if(!used) h[x]=-1;
    75             return used;
    76         }
    77     public:
    78         void dinic()
    79         {
    80             while(bfs())
    81                 ans+=dfs(S,inf);
    82         }
    83 };
    dinic

     Trie.

     1 #include<algorithm>
     2 #include<iostream>
     3 #include<cstring>
     4 #include<string>
     5 #include<cstdio>
     6 using namespace std;
     7 
     8 struct Node{
     9     Node* Alphabet[26];
    10     int count;bool isword;
    11 }root;
    12 
    13 struct Trie{
    14     Node* Create_node(){
    15         Node* node=(Node*)malloc(sizeof(root));
    16         node->count=false;
    17         node->isword=false;
    18         memset(node->Alphabet,NULL,sizeof(node->Alphabet));
    19         return node;
    20     }
    21     void Insert_word(char* str){
    22         Node* node=&root;
    23         char* word=str;
    24         int id;
    25         while(*word){
    26             id=*word-'a';
    27             if(node->Alphabet[id]==NULL)
    28                 node->Alphabet[id]=Create_node();
    29             node=node->Alphabet[id];
    30             ++word;
    31             node->count+=1;
    32         }
    33         node->isword=true;
    34     }
    35     int Query_word(char* str){
    36         Node* node=&root;
    37         char* word=str;
    38         int id;
    39         while(*word){
    40             id=*word-'a';
    41             if(node->Alphabet[id]==NULL)
    42                 return false;
    43             node=node->Alphabet[id];
    44             ++word;
    45         }
    46         return node->isword;
    47     }
    48 };
    Trie
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  • 原文地址:https://www.cnblogs.com/TheRoadToAu/p/7308859.html
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