生成JSON数据--官方方法

官方生成方法：

1）需要什么就给什么，要属性就给属性，要对象就给对象，要集合就给集合

2）添加都是使用put（）方法

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要求：

1.生成如下JSON数据：
{“age”:4,”name”:”zhagnsan”}

2.生成如下JSON数据：
[{“age”:4,”name”:”zhangsan”},{“age”:5,”name”:”lis”},{“age”:6,”name”:”wangw”}]

3.生成如下JSON数据：
{“no”:1,”name”:”android”,”employees”:[{“age”:3,”name”:”zhangsan”},{“age”:5,”name”:”lisi”},{“age”:2,”name”:”wangw”}]}

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第一题代码：

package com.qf.demo5;

import org.json.JSONException;
import org.json.JSONObject;

public class Test {

    public static void main(String[] args) {
        //生成如下JSON数据：{"age":4,"name":"zhagnsan"}
        JSONObject object = new JSONObject();// 产生json数据   不需要参数
        try {
            object.put("name", "zhagnsan");
            object.put("age", 4);
            System.out.println(object);
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

    }
}

---

第二题代码：

Person类

package com.qf.demo2;

public class Person {

    private int age;
    private String name;
    public Person(int age, String name) {
        super();
        this.age = age;
        this.name = name;
    }
    public Person() {
        super();
    }
    public int getAge() {
        return age;
    }
    public void setAge(int age) {
        this.age = age;
    }
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    @Override
    public String toString() {
        return "Person [age=" + age + ", name=" + name + "]";
    }


}

package com.qf.demo5;

import java.util.ArrayList;
import java.util.List;

import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import com.qf.demo2.Person;

public class Test2 {
    public static void main(String[] args) {
        //生成如下JSON数据：[{"age":4,"name":"zhangsan"},{"age":5,"name":"lis"},{"age":6,"name":"wangw"}]
        List<Person> list = new ArrayList<>();
        list.add(new Person(4, "zhangsan"));
        list.add(new Person(5, "lis"));
        list.add(new Person(6, "wangw"));

        JSONArray array = new JSONArray();
        for (int i = 0; i < list.size(); i++) {
            JSONObject object = new JSONObject();
            try {
                object.put("name", list.get(i).getName());
                object.put("age", list.get(i).getAge());
                array.put(object);
            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }
        System.out.println(array);
    }
}

第三题代码：

Person类：

package com.qf.demo2;

public class Person {

    private int age;
    private String name;
    public Person(int age, String name) {
        super();
        this.age = age;
        this.name = name;
    }
    public Person() {
        super();
    }
    public int getAge() {
        return age;
    }
    public void setAge(int age) {
        this.age = age;
    }
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    @Override
    public String toString() {
        return "Person [age=" + age + ", name=" + name + "]";
    }


}

package com.qf.demo5;

import java.util.ArrayList;
import java.util.List;

import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import com.qf.demo2.Person;

public class Test3 {

    public static void main(String[] args) {
        //生成如下JSON数据：{"no":1,"name":"android","employees":[{"age":3,"name":"zhangsan"},{"age":5,"name":"lisi"},{"age":2,"name":"wangw"}]}
        JSONObject object = new JSONObject();
        try {
            object.put("no", 1);
            object.put("name", "android");

            List<Person> persons = new ArrayList<>();
            persons.add(new Person(3, "zhangsan"));
            persons.add(new Person(5, "lisi"));
            persons.add(new Person(2, "wangw"));

            object.put("employees", persons);
            System.out.println(object);
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }
}