• Gps转高德经纬度坐标


    /// <summary>
        /// 转化工具类
        /// </summary>
        public class GPSTransToAMap
        {
            //椭球参数
            static double pi = 3.14159265358979324;
            static double a = 6378245.0;
            static double ee = 0.00669342162296594323;
    
            /// <summary>
            /// Gps转高德
            /// </summary>
            /// <param name="wgLat">GPS维度</param>
            /// <param name="wgLon">GPS经度</param>
            /// <param name="latlng">转化后的坐标</param>
            public static double[] transform(double wgLat, double wgLon)
            {
                double[] latlng = new double[2];//转化后的坐标
                if (outOfChina(wgLat, wgLon))
                {
                    latlng[0] = wgLat;
                    latlng[1] = wgLon;
                    return latlng;
                }
                double dLat = transformLat(wgLon - 105.0, wgLat - 35.0);
                double dLon = transformLon(wgLon - 105.0, wgLat - 35.0);
                double radLat = wgLat / 180.0 * pi;
                double magic = Math.Sin(radLat);
                magic = 1 - ee * magic * magic;
                double sqrtMagic = Math.Sqrt(magic);
                dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
                dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi);
                latlng[0] = wgLat + dLat;
                latlng[1] = wgLon + dLon;
                return latlng;
            }
    
            private static Boolean outOfChina(double lat, double lon)
            {
                if (lon < 72.004 || lon > 137.8347)
                    return true;
                if (lat < 0.8293 || lat > 55.8271)
                    return true;
                return false;
            }
    
            private static double transformLat(double x, double y)
            {
                double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.Sqrt(Math.Abs(x));
                ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0;
                ret += (20.0 * Math.Sin(y * pi) + 40.0 * Math.Sin(y / 3.0 * pi)) * 2.0 / 3.0;
                ret += (160.0 * Math.Sin(y / 12.0 * pi) + 320 * Math.Sin(y * pi / 30.0)) * 2.0 / 3.0;
                return ret;
            }
    
            private static double transformLon(double x, double y)
            {
                double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.Sqrt(Math.Abs(x));
                ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0;
                ret += (20.0 * Math.Sin(x * pi) + 40.0 * Math.Sin(x / 3.0 * pi)) * 2.0 / 3.0;
                ret += (150.0 * Math.Sin(x / 12.0 * pi) + 300.0 * Math.Sin(x / 30.0 * pi)) * 2.0 / 3.0;
                return ret;
            }
            //————————————————
            //版权声明:本文为CSDN博主「m0_38004177」的原创文章,遵循 CC 4.0 BY-SA 版权协议,转载请附上原文出处链接及本声明。
            //原文链接:https://blog.csdn.net/m0_38004177/article/details/93974126
        }
  • 相关阅读:
    TV
    [转载]如果看了这篇文章你还不懂傅里叶变换,那就过来掐死我吧
    search result
    floating-camera
    HDU 1032.The 3n + 1 problem【注意细节】【预计数据不强】【8月21】
    C语言socket send()数据缓存问题
    Marlin固件之—:基础入门与測试
    java语句顺序有时非常重要
    Android Studio 使用正式签名进行调试
    插入排序、交换排序、选择排序、归并排序、基数排序
  • 原文地址:https://www.cnblogs.com/SmilePastaLi/p/12100375.html
Copyright © 2020-2023  润新知