题目:
solution:
二分这个平均值,然后每个数都减去这个平均值,判断这个新序列是否有长度大于等于F的子序列的和大于0。
代码:
#include<cstdio>
#include<iostream>
using namespace std;
double qzh[100005];
int a[100005];
int main()
{
int n,f;
scanf("%d%d",&n,&f);
for(int i=1;i<=n;i++)
{
scanf("%d",&a[i]);
}
//printf("%d %d
",n,f);
//for(int i=1;i<=n;i++)
//{
// printf("%lf
",a[i]);
//}
double l=0,r=2000;
while(l+0.000001<=r)
{
double mid=(l+r)/2;
for(int i=1;i<=n;i++)
{
qzh[i]=qzh[i-1]+a[i]-mid;
}
double ans=-300000000,minn=300000000;
for(int i=f;i<=n;i++)
{
minn=min(minn,qzh[i-f]);
ans=max(ans,qzh[i]-minn);
}
if(ans>=0)l=mid;
else
r=mid;
}
printf("%d
",(int)(r*1000));
//printf("%d
",(int)(l+0.5));
//int last=(int)(l*1000+0.5);
//printf("%d
",last);
}