• [LeetCode]Sum Root to Leaf Numbers


    Sum Root to Leaf Numbers

    Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

    An example is the root-to-leaf path 1->2->3 which represents the number 123.

    Find the total sum of all root-to-leaf numbers.

    For example,

        1
       / 
      2   3

    The root-to-leaf path 1->2 represents the number 12.
    The root-to-leaf path 1->3 represents the number 13.

    Return the sum = 12 + 13 = 25.

    递归深搜,一类题。

     1 /**
     2  * Definition for a binary tree node.
     3  * struct TreeNode {
     4  *     int val;
     5  *     TreeNode *left;
     6  *     TreeNode *right;
     7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     8  * };
     9  */
    10 class Solution {
    11 public:
    12     void dfs(TreeNode* root,int num,int& result)
    13     {
    14         num=num*10+root->val;
    15         if(root->left==NULL && root->right==NULL)
    16         {
    17             result+=num;
    18             return;
    19         }
    20         if(root->left) dfs(root->left,num,result);
    21         if(root->right) dfs(root->right,num,result);
    22     }
    23     int sumNumbers(TreeNode* root) {
    24         if(!root) return 0;
    25         int num=0,result=0;
    26         dfs(root,num,result);
    27         return result;
    28     }
    29 };
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  • 原文地址:https://www.cnblogs.com/Sean-le/p/4813855.html
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