![](https://images.cnblogs.com/OutliningIndicators/ContractedBlock.gif)
用1.2....9,这九个数字,组成三个三位数,要求每个数字只能用一次,而且,三个数字成比例,1:2:3 下面是代码 #include<stdio.h> int main() { int i,x,y,z,a,b,c; for(i = 123;i < 329; i++) { x = i; int f[10] = {0},flag = 0; y = 2*x; z = 3*x; a = x; b = y; c = z; while(x) { if(f[x%10]) { flag = 1; break; } else f[x%10] = 1; x /= 10; } if(flag) continue; while(y) { if(f[y%10]) { flag = 1; break; } else f[y%10] = 1; y /= 10; } if(flag) continue; while(z) { if(f[z%10]) { flag = 1; break; } else f[z%10] = 1; z /= 10; } if(flag) continue; printf("%d %d %d\n",a,b,c); } return 0; } 感言,做ACM有时候要冷静冷静再继续,要不会再小的误区给憋死....