• 水题 Codeforces Round #302 (Div. 2) A Set of Strings


    题目传送门

     1 /*
     2     题意:一个字符串分割成k段,每段开头字母不相同
     3     水题:记录每个字母出现的次数,每一次分割把首字母的次数降为0,最后一段直接全部输出
     4 */
     5 #include <cstdio>
     6 #include <iostream>
     7 #include <cstring>
     8 #include <string>
     9 #include <algorithm>
    10 using namespace std;
    11 
    12 const int MAXN = 1e2 + 10;
    13 const int INF = 0x3f3f3f3f;
    14 char s[MAXN];
    15 int num[30];
    16 
    17 int main(void)        //Codeforces Round #302 (Div. 2) A Set of Strings
    18 {
    19     //freopen ("A.in", "r", stdin);
    20 
    21     int k;
    22     while (scanf ("%d", &k) == 1)
    23     {
    24         scanf ("%s", &s);
    25         if (k == 1)    {puts ("YES");    printf ("%s
    ", s);    continue;}
    26 
    27         memset (num, 0, sizeof (num));
    28         int len = strlen (s);
    29         for (int i=0; i<len; ++i)    num[s[i]-'a']++;
    30         int t = 0;
    31         for (int i=0; i<26; ++i)    if (num[i])    ++t;
    32         if (t < k)    {puts ("NO");    continue;}
    33 
    34         puts ("YES");
    35         printf ("%c", s[0]);    num[s[0]-'a'] = 0;
    36         int p = 0;    int i;
    37         for (i=1; i<len; ++i)
    38         {
    39             if (!num[s[i]-'a'])    {printf ("%c", s[i]);}
    40             else
    41             {
    42                 num[s[i]-'a'] = 0;    puts ("");
    43                 printf ("%c", s[i]);    ++p;
    44             }
    45             if (p == k - 1)    break;
    46         }
    47 
    48         for (int j=i+1; j<len; ++j)    printf ("%c", s[j]);
    49         puts ("");
    50     }
    51 
    52     return 0;
    53 }
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  • 原文地址:https://www.cnblogs.com/Running-Time/p/4488690.html
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