HDU 1260 Tickets

令dp[i]为前i个人买好票的最少花费。

那么这个状态可由2种状态转移而来：1.上一个人和自己组队买票 2.上一个人不和自己组队买票

即可得：dp[i] = min(dp[i-1]+cost[i], dp[i-2]+together[i]);

#include <iostream>
#include <bits/stdc++.h>
using namespace std;

#define ll long long
#define mst(a,b) memset(a,b,sizeof(a))
#define rep(i,a,b) for(ll i=(a);i<(b);++i)
#define scf(n) scanf("%d", &(n));
const double eps = 1e-8, PI = acos(-1.0f);
const int inf = 0x3f3f3f3f, maxN = 1e5 + 5;
const int maxT = 2005;
int N, M, T;

int ti[maxT];
int yq[maxT];

// dp[i]即前i个人买票最少花费
int dp[maxT];

int main() {
    int K;
    scf(T);
    while (T--) {
        scanf("%d", &K);
        rep(i, 1, K + 1) scf(ti[i]);
        rep(i, 2, K + 1) scf(yq[i]);

        dp[0] = 0;
        for (int i = 1; i <= K; ++i) {
            int d1, d2 = inf;
            d1 = dp[i - 1] + ti[i];
            if (i - 2 >= 0)
                d2 = dp[i - 2] + yq[i];
            dp[i] = min(d1, d2);
        }
        int hh, mm, ss = dp[K];
        hh = ss / 3600;
        ss -= hh * 3600;
        mm = ss / 60;
        ss -= mm * 60;

        hh += 8;
        char fg[10];
        if (hh >= 12) strcpy(fg, "pm");
        else strcpy(fg, "am");
        printf("%02d:%02d:%02d %s
", hh, mm, ss, fg); 
    }
    return 0;
}