Given an unsorted array of integers, find the length of the longest consecutive elements sequence.
For example,
Given [100, 4, 200, 1, 3, 2]
,
The longest consecutive elements sequence is [1, 2, 3, 4]
. Return its length: 4
.
Your algorithm should run in O(n) complexity.
思考:空间换时间,查找O(1)用unordered_set。
class Solution { public: int longestConsecutive(vector<int> &num) { // Start typing your C/C++ solution below // DO NOT write int main() function unordered_set<int> existTable; for(int i = 0; i < num.size(); ++i) existTable.insert(num[i]); unordered_set<int> visitedTable; int mmax = INT_MIN; for(int i = 0; i < num.size(); ++i) { int curNum = num[i]; if(visitedTable.find(curNum) != visitedTable.end()) continue; int cnt = 1; //search left int left = curNum; while(existTable.find(--left) != existTable.end()) cnt++, visitedTable.insert(left); int right = curNum; while(existTable.find(++right) != existTable.end()) cnt++, visitedTable.insert(right); mmax = max(cnt, mmax); } return mmax; } };