• 【洛谷 P4213】 【模板】杜教筛(Sum)


    #include <bits/stdc++.h>
    using namespace std;
    #define ll long long 
    int cnt, n;
    map<int, long long> mpu, mpphi;
    int prime[10000010], mu[10000010], v[10000010], usum[10000010], phi[10000010];
    ll phisum[10000010];
    ll getusum(int n){
    	if(n <= 10000000) return usum[n];
    	if(mpu[n]) return mpu[n];
    	ll ans = 1;
    	for(ll l = 2, r = 0; l <= n; l = r + 1){
    		r = n / (n / l);
    		ans -= (r-l+1) * getusum(n / l);
    	}
    	return mpu[n] = ans;
    }
    ll getphisum(int n){
    	if(n <= 10000000) return phisum[n];
    	if(mpphi[n]) return mpphi[n];
    	ll ans = (ll)n * ((ll)n+1) / 2;
    	for(ll l = 2, r = 0; l <= n; l = r + 1){
    		r = n / (n / l);
    		ans -= (r-l+1) * getphisum(n / l);
    	}
    	return mpphi[n] = ans;
    }
    int T;
    int main(){
    	mu[1] = phi[1] = usum[1] = phisum[1] = 1; 
    	for(int i = 2; i <= 10000000; ++i){
    		if(!v[i]){ mu[i] = -1; phi[i] = i-1; prime[++cnt] = i; }
    		usum[i] = usum[i-1] + mu[i];
    		phisum[i] = phisum[i-1] + phi[i];
    		for(int j = 1; j <= cnt && (ll)i * prime[j] <= 10000000; ++j){
    			v[i * prime[j]] = 1;
    			if(i % prime[j] == 0){
    				phi[i * prime[j]] = phi[i] * prime[j];
    				break;
    			}
    			mu[i * prime[j]] = -mu[i];
    			phi[i * prime[j]] = phi[i] * (prime[j] - 1);
    		}
    	}
    	scanf("%d", &T);
    	while(T--){
    		mpu.clear(); mpphi.clear();
    		scanf("%d", &n);
    		printf("%lld %lld
    ", getphisum(n), getusum(n));
    	}
    }
    
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  • 原文地址:https://www.cnblogs.com/Qihoo360/p/15302328.html
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