• 【BZOJ 2351】Matrix(Hash)


    题目链接
    二维(Hash)类似二维前缀和,每一行看成一个(h)进制数,每一个以(1,1)为左上角的矩阵看成一个由每一行的(Hash)值组成的(l)进制数。
    然后自己推推柿子就行。

    #include <cstdio>
    #include <cstring>
    #include <map>
    using namespace std;
    #define Open(s) freopen(s".in","r",stdin); freopen(s".out","w",stdout);
    #define h 1331
    #define l 2333
    int n, m, r, c, T;
    map <unsigned long long, int> mp;
    unsigned long long hs[1010][1010], ph[1010], pl[1010], xs[1010][1010];
    char ch;
    int main(){
        Open("matrix"); ph[0] = pl[0] = 1;
        scanf("%d%d%d%d", &n, &m, &r, &c);
        for(int i = 1; i <= n; ++i)
            for(int j = 1; j <= m; ++j){
                ch = getchar();
                while(ch != '0' && ch != '1') ch = getchar();
                hs[i][j] = hs[i][j - 1] * h + ch;
            }
        for(int i = 1; i <= n; ++i)
            for(int j = 1; j <= m; ++j)
            	hs[i][j] += hs[i - 1][j] * l;
        for(int i = 1; i <= m; ++i) ph[i] = ph[i - 1] * h;
    	for(int i = 1; i <= n; ++i) pl[i] = pl[i - 1] * l; 
        for(int i = r; i <= n; ++i)
        	for(int j = c; j <= m; ++j)
        		mp[hs[i][j] - hs[i - r][j] * pl[r] - hs[i][j - c] * ph[c] + hs[i - r][j - c] * pl[r] * ph[c]] = 1;
        scanf("%d", &T);
        while(T--){
        	for(int i = 1; i <= r; ++i)
                for(int j = 1; j <= c; ++j)
                	xs[i][j] = 0;
            for(int i = 1; i <= r; ++i)
                for(int j = 1; j <= c; ++j){
                    ch = getchar();
                    while(ch != '0' && ch != '1') ch = getchar();
                    xs[i][j] = xs[i][j - 1] * h + ch;
                }
            for(int i = 1; i <= r; ++i)
                for(int j = 1; j <= c; ++j)
                	xs[i][j] += xs[i - 1][j] * l;
            printf("%d
    ", mp[xs[r][c]]);
        }
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/Qihoo360/p/11224239.html
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