Question:
Given a sorted array of n integers that has been rotated an unknown number of times, write code to find an element in the array. You may assume that the array was originally sorted in increasing order.
1 package POJ; 2 3 import java.util.Arrays; 4 import java.util.Comparator; 5 import java.util.Hashtable; 6 import java.util.LinkedList; 7 import java.util.List; 8 9 public class Main { 10 11 /** 12 * 13 * 11.3 Given a sorted array of n integers that has been rotated an unknown number of times, write code to find an 14 * element in the array. You may assume that the array was originally sorted in increasing order. 15 * 16 */ 17 public static void main(String[] args) { 18 Main so = new Main(); 19 int[] list = { 10, 15, 20, 0, 5 }; 20 System.out.println(so.search(list, 0, 4, 5)); 21 } 22 23 public int search(int[] list, int left, int right, int x) { 24 int mid = (right + left) / 2; 25 if (x == list[mid]) 26 return mid; 27 if (left > right) 28 return -1; 29 if (list[left] < list[mid]) { 30 // left is normally ordered 31 if (x >= list[left] && x <= list[mid]) { 32 return search(list, left, mid - 1, x); 33 } else { 34 return search(list, mid + 1, right, x); 35 } 36 } else if (list[left] > list[mid]) { 37 // right is normally ordered 38 if (x >= list[mid] && x <= list[right]) { 39 return search(list, mid + 1, right, x); 40 } else { 41 return search(list, left, mid - 1, x); 42 } 43 } else { 44 // list[left]==list[mid] 45 // left half is all repeats 46 if (list[mid] != list[right]) { 47 return search(list, mid + 1, right, x); 48 } else { 49 // search both halves 50 int result = search(list, left, mid - 1, x); 51 if (result == -1) 52 return search(list, mid + 1, right, x); 53 else 54 return result; 55 } 56 } 57 } 58 }