• AT5256 [ABC142F] Pure(有向图求最小环)


    传送门

    思路:

    枚举每个点作为原点,求最小环长度。
    关于求最小环,将spfa算法改为:将与原点所连的所有点放入队列。
    输出方案的话,维护前驱数组记录是如何转移的。
    推荐一篇很好的博客

    代码:

    #include <iostream>
    #include <algorithm>
    #include <cstdio>
    #include <cstring>
    #include <cmath>
    #include<map>
    #include<set>
    #include<vector>
    #include<queue>
    using namespace std;
    typedef long long ll;
    typedef unsigned long long ull;
    typedef pair<ll, ll>PLL;
    typedef pair<int, int>PII;
    typedef pair<double, double>PDD;
    #define I_int ll
    inline ll read()
    {
        ll x = 0, f = 1;
        char ch = getchar();
        while(ch < '0' || ch > '9')
        {
            if(ch == '-')f = -1;
            ch = getchar();
        }
        while(ch >= '0' && ch <= '9')
        {
            x = x * 10 + ch - '0';
            ch = getchar();
        }
        return x * f;
    }
    #define read read()
    #define closeSync ios::sync_with_stdio(0);cin.tie(0);cout.tie(0)
    #define multiCase int T;cin>>T;for(int t=1;t<=T;t++)
    #define rep(i,a,b) for(int i=(a);i<=(b);i++)
    #define repp(i,a,b) for(int i=(a);i<(b);i++)
    #define per(i,a,b) for(int i=(a);i>=(b);i--)
    #define perr(i,a,b) for(int i=(a);i>(b);i--)
    ll ksm(ll a, ll b, ll p)
    {
        ll res = 1;
        while(b)
        {
            if(b & 1)res = res * a % p;
            a = a * a % p;
            b >>= 1;
        }
        return res;
    }
    const int inf = 0x3f3f3f3f;
    #define PI acos(-1)
    const int maxn=1100;
    
    vector<int>g[maxn];
    int n,m,mp[maxn][maxn],dis[maxn],pre[maxn],res[maxn],st[maxn];
    
    int spfa(int s){
        memset(st,0,sizeof st);
        queue<int>q;
        memset(dis,0x3f,sizeof dis);
        for(int i=0;i<g[s].size();i++){
            int j=g[s][i];
            pre[j]=s;
            st[j]=1;
            dis[j]=1;
            q.push(j);
        }
        while(!q.empty()){
            int t=q.front();q.pop();
            st[t]=0;
            for(int i=0;i<g[t].size();i++){
                int j=g[t][i];
                if(dis[j]>dis[t]+1){
                    dis[j]=dis[t]+1;
                    pre[j]=t;
                    if(!st[j]){
                        st[j]=1;
                        q.push(j);
                    }
                }
            }
        }
        return dis[s];
    }
    
    int main()
    {
        n=read,m=read;
        rep(i,1,m){
            int u=read,v=read;
            g[u].push_back(v);
            mp[u][v]=1;
        }
        int minn=inf,s=-1;
        for(int i=1;i<=n;i++){
            int tmp=spfa(i);
            if(tmp<minn){
                minn=tmp;
                s=i;
                for(int j=1;j<=n;j++) res[j]=pre[j];
            }
        }
        if(minn==inf){
            puts("-1");
        }
        else{
            printf("%d
    ",minn);
            vector<int>path;
            int now=s;
            while(res[now]!=s){
                path.push_back(now);
                now=res[now];
            }
            path.push_back(now);
            reverse(path.begin(),path.end());
            for(int i=0;i<path.size();i++)
                cout<<path[i]<<endl;
        }
        return 0;
    }
    
    /*
    
    **/
    
    
    
    
    
    
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  • 原文地址:https://www.cnblogs.com/OvOq/p/14839012.html
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