package operator;
public class Demo01 {
public static void main(String[] args) {
//二元运算符
int a = 10;
int b = 20;
int c = 30;
int d = 40;
System.out.println(a+b);
System.out.println(a-b);
System.out.println(a*b);
System.out.println((double)a/b);
}
}
package operator;
public class Demo04 {
public static void main(String[] args) {
//++ -- 自增,自减 一元运算符
int a = 3;
int b = a++; //执行完这行代码后,先给b赋值,再自增
//a = a + 1;
System.out.println(a);
int c = ++a; //执行完这行代码前,先自增,再给c赋值
System.out.println(a);
System.out.println(b);
System.out.println(c);
//幂运算 3^2 = 9,Math数学运算类
double pow = Math.pow(3, 2);
System.out.println(pow);
}
}
package operator;
public class Demo05 {
public static void main(String[] args) {
//与(and),或(or),非(!)
boolean a = true;
boolean b = false;
System.out.println("a && b: "+(a&&b)); //逻辑与运算:两个变量为真,结果为true
System.out.println("a || b: "+(a||b)); //逻辑或运算,两个变量有一个为真,结果为true
System.out.println("!(a && b): "+!(a&&b)); //逻辑非运算,如果是真则为假,如果是假则为真
//短路运算
int c = 5;
boolean d = (c<4)&&(c++<4);
System.out.println(d);
System.out.println(c);//5
}
}
package operator;
public class Demo06 {
public static void main(String[] args) {
/*
A = 0011 1100
B = 0000 1101
位运算
A&B = 0000 1100 A与B上下两数相比较两位都是1,结果才为1
A|B = 0011 1101 A或B上下两数相比较任意一边是1,结果为1
A^B = 0011 0001 亦或如果上下两数相同则为0,否则为1
~B = 1111 0010 取反B
2*8 = 16 2*2*2*2
<< 左移 每移一位*2
>> 右移 每移一位/2
0000 0000 0
0000 0001 1
0000 0010 2
0000 0011 3
0000 0100 4
0000 1000 8
0001 0000 16
*/
System.out.println(2<<3);//16
System.out.println(2<<5);//64
System.out.println(3<<3);//24
System.out.println(5<<3);//40
}
}
package operator;
public class Demo07 {
public static void main(String[] args) {
int a = 10;
int b = 20;
a+=b; //a = a+b
a-=b; //a = a-b
System.out.println(a);
//字符串连接符 + String
System.out.println(""+a+b);//1020 String类型在前,类型转为String类型
System.out.println(a+b+"");//30 int类型在前先运算,后转换为String类型
}
}
package operator;
//三元运算符
public class Demo08 {
public static void main(String[] args) {
// x ? y : z
//如果x==true,则结果为y,否则结果为z
int score = 80;
String type = score < 60 ?"不及格":"及格";//必须掌握
System.out.println(type);
}
}