• 【全网最高端】中缀表达式转为后缀表达式以及求值(可用于负数,阶乘,高精度)


    代码里有注释。。。直接上代码。。。

    #include<bits/stdc++.h>
    #define rep(i,k,n) for(int i=k;i<=n;i++)
    #define per(i,n,k) for(int i=n;i>=k;i--)
    #define pii pair<int,int>
    #define pb push_back
    #define mp make_pair
    #define re return
    #define se second
    #define fi first
    using namespace std;
    //---------------------------------------------------------------head----------------------------------------------------------------------
    struct BigInteger {
        typedef unsigned long long LL;
    
        static const int BASE = 100000000;
        static const int WIDTH = 8;
        vector<int> s;
    
        BigInteger& clean(){while(!s.back()&&s.size()>1)s.pop_back(); return *this;}
        BigInteger(LL num = 0) {*this = num;}
        BigInteger(string s) {*this = s;}
        BigInteger& operator = (long long num) {
            s.clear();
            do {
                s.push_back(num % BASE);
                num /= BASE;
            } while (num > 0);
            return *this;
        }
        BigInteger& operator = (const string& str) {
            s.clear();
            int x, len = (str.length() - 1) / WIDTH + 1;
            for (int i = 0; i < len; i++) {
                int end = str.length() - i*WIDTH;
                int start = max(0, end - WIDTH);
                sscanf(str.substr(start,end-start).c_str(), "%d", &x);
                s.push_back(x);
            }
            return (*this).clean();
        }
    
        BigInteger operator + (const BigInteger& b) const {
            BigInteger c; c.s.clear();
            for (int i = 0, g = 0; ; i++) {
                if (g == 0 && i >= s.size() && i >= b.s.size()) break;
                int x = g;
                if (i < s.size()) x += s[i];
                if (i < b.s.size()) x += b.s[i];
                c.s.push_back(x % BASE);
                g = x / BASE;
            }
            return c;
        }
        BigInteger operator - (const BigInteger& b) const {
            assert(b <= *this); // 减数不能大于被减数
            BigInteger c; c.s.clear();
            for (int i = 0, g = 0; ; i++) {
                if (g == 0 && i >= s.size() && i >= b.s.size()) break;
                int x = s[i] + g;
                if (i < b.s.size()) x -= b.s[i];
                if (x < 0) {g = -1; x += BASE;} else g = 0;
                c.s.push_back(x);
            }
            return c.clean();
        }
        BigInteger operator * (const BigInteger& b) const {
            int i, j; LL g;
            vector<LL> v(s.size()+b.s.size(), 0);
            BigInteger c; c.s.clear();
            for(i=0;i<s.size();i++) for(j=0;j<b.s.size();j++) v[i+j]+=LL(s[i])*b.s[j];
            for (i = 0, g = 0; ; i++) {
                if (g ==0 && i >= v.size()) break;
                LL x = v[i] + g;
                c.s.push_back(x % BASE);
                g = x / BASE;
            }
            return c.clean();
        }
        BigInteger operator / (const BigInteger& b) const {
            assert(b > 0);  // 除数必须大于0
            BigInteger c = *this;       // 商:主要是让c.s和(*this).s的vector一样大
            BigInteger m;               // 余数:初始化为0
            for (int i = s.size()-1; i >= 0; i--) {
                m = m*BASE + s[i];
                c.s[i] = bsearch(b, m);
                m -= b*c.s[i];
            }
            return c.clean();
        }
        BigInteger operator % (const BigInteger& b) const { //方法与除法相同
            BigInteger c = *this;
            BigInteger m;
            for (int i = s.size()-1; i >= 0; i--) {
                m = m*BASE + s[i];
                c.s[i] = bsearch(b, m);
                m -= b*c.s[i];
            }
            return m;
        }
    
        int bsearch(const BigInteger& b, const BigInteger& m) const{
            int L = 0, R = BASE-1, x;
            while (1) {
                x = (L+R)>>1;
                if (b*x<=m) {if (b*(x+1)>m) return x; else L = x;}
                else R = x;
            }
        }
        BigInteger& operator += (const BigInteger& b) {*this = *this + b; return *this;}
        BigInteger& operator -= (const BigInteger& b) {*this = *this - b; return *this;}
        BigInteger& operator *= (const BigInteger& b) {*this = *this * b; return *this;}
        BigInteger& operator /= (const BigInteger& b) {*this = *this / b; return *this;}
        BigInteger& operator %= (const BigInteger& b) {*this = *this % b; return *this;}
    
        bool operator < (const BigInteger& b) const {
            if (s.size() != b.s.size()) return s.size() < b.s.size();
            for (int i = s.size()-1; i >= 0; i--)
                if (s[i] != b.s[i]) return s[i] < b.s[i];
            return false;
        }
        bool operator >(const BigInteger& b) const{return b < *this;}
        bool operator<=(const BigInteger& b) const{return !(b < *this);}
        bool operator>=(const BigInteger& b) const{return !(*this < b);}
        bool operator!=(const BigInteger& b) const{return b < *this || *this < b;}
        bool operator==(const BigInteger& b) const{return !(b < *this) && !(b > *this);}
    };
    
    ostream& operator << (ostream& out, const BigInteger& x) {
        out << x.s.back();
        for (int i = x.s.size()-2; i >= 0; i--) {
            char buf[20];
            sprintf(buf, "%08d", x.s[i]);
            for (int j = 0; j < strlen(buf); j++) out << buf[j];
        }
        return out;
    }
    
    istream& operator >> (istream& in, BigInteger& x) {
        string s;
        if (!(in >> s)) return in;
        x = s;
        return in;
    }
    stack<BigInteger> si;
    stack<char> sc;
    vector<BigInteger> vc;
    bool isnum[1005];
    bool flag=0;
    BigInteger pow(BigInteger a,BigInteger b){BigInteger base=a,ans=1;while(b!=0){if(b%2==1)ans*=base;base*=base;b/=2;}return ans;}
    BigInteger clas(char c)//符号优先级 
    {
    	if(c=='(' || c==')') re 0;
    	if(c=='+' || c=='-') re 1;
    	if(c=='*' || c=='/') re 2;
    	if(c=='^') re 3;
    	re 4;
    }
    BigInteger cal(BigInteger a,BigInteger b,BigInteger c)//符号求值 
    {
    	BigInteger ans=1;
    	if(c=='+') re a+b;
    	if(c=='-') re b-a;
    	if(c=='*') re a*b;
    	if(c=='/') re b/a;
    	re pow(b,a);
    }
    int main()
    {
    	string s;cin>>s;
    	s="("+s+")";//可以用来防止栈为空找top时的溢出情况 
    	int n=(int)s.size();
    	rep(i,0,n-1)
    	{
    		if(s[i]=='(')//左括号直接压入 
    		{
    			sc.push(s[i]);
    			continue;
    		}
    		if(s[i]==')')//找到右括号将栈清空到左括号为止 
    		{
    			char c=sc.top();sc.pop();
    			while(c!='(')
    			{
    				vc.pb(c);
    				c=sc.top();sc.pop();
    			}
    			continue;
    		}
    		if(s[i]>='0' && s[i]<='9')//数字 
    		{
    			BigInteger sum=0;
    			while(s[i]>='0' && s[i]<='9')
    			sum=sum*10+s[i++]-'0';
    			if(flag)
    			sum=BigInteger(-1)*sum,flag=0;
    			vc.pb(sum);
    			isnum[vc.size()-1]=1;
    			i--;continue;
    		}
    		if(s[i]=='-' && (clas(s[i-1])!=4 && s[i-1]!=')'))
    		{
    			flag=1;
    			continue;
    		}
    		while(!sc.empty() && clas(s[i])<=clas(sc.top()))//如果是符号就找到第一个优先级比他小的 
    		vc.pb(sc.top()),sc.pop();
    		sc.push(s[i]);
    	}
    	while(!sc.empty())//清空栈 
    	vc.pb(sc.top()),sc.pop();
    	rep(i,0,vc.size()-1)//根据后缀表达式求值 
    	{
    		if(!isnum[i])
    		{
    			BigInteger a=si.top();si.pop();
    			BigInteger b=si.top();si.pop();
    			BigInteger ans=cal(a,b,vc[i]);
    			si.push(ans);
    		} 
    		else
    		si.push(vc[i]);
    	}
    	cout<<si.top();
    	return 0;
    }
    //----------------------------------------------------------------end----------------------------------------------------------------------
    
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  • 原文地址:https://www.cnblogs.com/NightRaven/p/9802134.html
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