• 【Python】回文palindrome——利用字符串反转


    回文

    palindrome

    Python

    字符串反转string[::-1]

    Slice notation "[a : b : c]" means "count in increments of c starting at a inclusive, up to b exclusive".

    If c is negative you count backwards, if omitted it is 1.

    If a is omitted then you start as far as possible in the direction you're counting from (so that's the start if c is positive and the end if negative).

    If b is omitted then you end as far as possible in the direction you're counting to (so that's the end if c is positive and the start if negative).
    If a or b is negative it's an offset from the end (-1 being the last character) instead of the start.

    回文
    
    ###############################################
    #       Exercise by Websten from forums       #
    ###############################################
    # A palindrome is a word or a phrase that reads 
    # the same backwards as forwards. Make a program 
    # that checks if a word is a palindrome. 
    # If the word is a palindrome, print 0 to the terminal,
    # -1 otherwise. 
    # The word contains lowercase letters a-z and 
    # will be at least one character long.
    #
    ### HINT! ###
    # You can read a string backwards with the following syntax:
    # string[::-1] - where the "-1" means one step back.
    # This exercise can be solved with only unit 1 knowledge
    # (no loops or conditions)
    
    word = "madman"
    # test case 2
    # word = "madman" # uncomment this to test
    
    ###
    # YOUR CODE HERE. DO NOT DELETE THIS LINE OR ADD A word DEFINITION BELOW IT.
    ###
    #自己的代码
    is_palindrome = word.find(word[::-1])
    
    # TESTING
    print is_palindrome
    # >>> 0  # outcome if word == "madam",a palindrome
    # >>> -1 # outcome if word == "madman",not a palindrome
    
  • 相关阅读:
    字符串----基础训练(一)
    多维数组和矩阵----子矩阵最大累加和
    多维数组和矩阵----子数组最大累加和
    多维数组和矩阵----边界为1的最大子方阵
    多维数组和矩阵----基础训练
    数组的包含
    数组能排成的最小数(特殊排序)
    堆排序应用之topK问题
    需要排序的最短子数组长度
    排序数组中找和的因子
  • 原文地址:https://www.cnblogs.com/Neo007/p/7398870.html
Copyright © 2020-2023  润新知