• COGS 2259 异化多肽——生成函数+多项式求逆


    题目:http://cogs.pro:8080/cogs/problem/problem.php?pid=2259

    详见:https://www.cnblogs.com/Zinn/p/10054569.html

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #define ll long long
    using namespace std;
    const int N=1e5+5,M=(1<<18)+5,mod=1005060097,g=5;
    int n,a[M],b[M],A[M],len,r[M],c[M];
    int rdn()
    {
      int ret=0;bool fx=1;char ch=getchar();
      while(ch>'9'||ch<'0'){if(ch=='-')fx=0;ch=getchar();}
      while(ch>='0'&&ch<='9') ret=ret*10+ch-'0',ch=getchar();
      return fx?ret:-ret;
    }
    void upd(int &x){x>=mod?x-=mod:0;}
    int pw(int x,int k)
    {int ret=1;while(k){if(k&1)ret=(ll)ret*x%mod;x=(ll)x*x%mod;k>>=1;}return ret;}
    void ntt(int *a,bool fx)
    {
      for(int i=0;i<len;i++)
        if(i<r[i])swap(a[i],a[r[i]]);
      for(int R=2;R<=len;R<<=1)
        {
          int wn=pw( g,fx?(mod-1)-(mod-1)/R:(mod-1)/R );
          for(int i=0,m=R>>1;i<len;i+=R)
        for(int j=0,w=1;j<m;j++,w=(ll)w*wn%mod)
          {
            int x=a[i+j], y=(ll)w*a[i+m+j]%mod;
            a[i+j]=x+y; upd(a[i+j]);
            a[i+m+j]=x+mod-y; upd(a[i+m+j]);
          }
        }
      if(!fx)return ; int inv=pw(len,mod-2);
      for(int i=0;i<len;i++)a[i]=(ll)a[i]*inv%mod;
    }
    void getinv(int n,int *a,int *b)
    {
      if(n==1){b[0]=pw(a[0],mod-2);return;}
      getinv(n+1>>1,a,b);
      for(len=1;len<n<<1;len<<=1);
      for(int i=0;i<len;i++)r[i]=(r[i>>1]>>1)+((i&1)?len>>1:0);
      for(int i=0;i<n;i++)A[i]=a[i]; for(int i=n;i<len;i++)A[i]=0;
      ntt(A,0); ntt(b,0);
      for(int i=0;i<len;i++)b[i]=(2-(ll)A[i]*b[i])%mod*b[i]%mod+mod,upd(b[i]);
      ntt(b,1);
      for(int i=n;i<len;i++)b[i]=0;
    }
    int main()
    {
      freopen("polypeptide.in","r",stdin);
      freopen("polypeptide.out","w",stdout);
      n=rdn();int m;m=rdn();
      for(int i=1,d;i<=m;i++)
        {
          d=rdn();
          a[d]+=mod-1,upd(a[d]);
        }
      a[0]++; upd(a[0]);
      getinv(n+1,a,b);
      printf("%d
    ",b[n]);
      return 0;
    }
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  • 原文地址:https://www.cnblogs.com/Narh/p/10054629.html
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