• HDU


    版本一:

     1 #include<bits/stdc++.h>
     2 #define IO ios_base::sync_with_stdio(0);cin.tie(0);
     3 using namespace std;
     4 int prime[32770], phi[32770];
     5 int main()
     6 {IO;
     7     int T;
     8     cin >> T;
     9     while(T --){
    10         int n;
    11         cin >> n;
    12         memset(prime, 1, sizeof(prime));
    13         prime[0] = 0;
    14         prime[1] = 0;
    15         for(int i = 2; i * i <= n; i ++){
    16             if(prime[i]){
    17                 for(int j = i + i; j <= n; j += i){
    18                     prime[j] = 0;
    19                 }
    20             }
    21         }//找到所有n以内的素数
    22         for(int i = 1; i <= n; i ++)
    23             phi[i] = i;
    24         for(int i = 2; i <= n; i ++){
    25             if(prime[i]){
    26                 for(int j = i; j <= n; j += i){
    27                     phi[j] = phi[j] / i * (i - 1);
    28                 }
    29             }
    30         }//求出n以内所有数的欧拉值
    31         cout << phi[n] << endl;
    32     }
    33 }
    View Code

    版本二:

     1 #include<bits/stdc++.h>
     2 #define IO ios_base::sync_with_stdio(0);cin.tie(0);
     3 using namespace std;
     4 int prime[32770], u[32770], phi[32770];
     5 int main()
     6 {IO;
     7     int T;
     8     cin >> T;
     9     while(T --){
    10         int n;
    11         cin >> n;
    12         int sum = 0;
    13         phi[1] = 1;
    14         memset(u, 1, sizeof(u));
    15         for(int i = 2; i <= n; i ++){
    16             if(u[i]){
    17                 prime[++ sum] = i;
    18                 phi[i] = i - 1;
    19             }
    20             for(int j = 1; j <= sum; j ++){
    21                 if(i * prime[j] > n) break;
    22                 u[i * prime[j]] = 0;
    23                 if(i % prime[j]){
    24                    phi[i * prime[j]] = phi[i] * (prime[j] - 1);
    25                 }
    26                 else{
    27                     phi[i * prime[j]] = phi[i] * prime[j];
    28                 }
    29             }
    30         }
    31         cout << phi[n] << endl;
    32     }
    33 }
    View Code
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  • 原文地址:https://www.cnblogs.com/NWUACM/p/6399061.html
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