• KMP几道入门题目


    HDU 1711 Number Sequence(模板题)

    #include<stdio.h>
    #include<string>
    const int maxn=1e6+10;
    const int maxm=1e4+10;
    int t,n,m,s[maxn],p[maxn];
    int next[maxm];
    void GetNext()
    {
        int plen=0;
        int slen=-1;
        next[0]=-1;
        while(plen<m)
        {
            if(slen==-1||p[plen]==p[slen])
            {
                plen++;slen++;
                if(p[plen]!=p[slen])next[plen]=slen;
                else next[plen]=next[slen];
            }
            else slen=next[slen];
        }
    }
    int kmp()
    {
        int plen=0;
        int slen=0;
        while(plen<m&&slen<n)
        {
            if(plen==-1||p[plen]==s[slen])
            {
                plen++;slen++;
            }
            else plen=next[plen];
        }
        if(plen==m)
        return slen-plen+1;
        else return -1;
    }
    int main()
    {
        scanf("%d",&t);
        while(t--)
        {
            scanf("%d%d",&n,&m);
            for(int i=0;i<n;i++)scanf("%d",&s[i]);
            for(int i=0;i<m;i++)scanf("%d",&p[i]);
            GetNext();
            printf("%d
    ",kmp());
        }
        return 0;
    }
    View Code

     HDU 2087 剪花布条

    求一个串在另一个串中的出现次数,KMP模板题

    #include<iostream>
    #include<string>
    using namespace std;
    string s,p;
    int plen,slen,Next[1010];
    void GetNext()
    {
        int j=0;
        int k=-1;
        Next[0]=-1;
        while(j<plen)
        {
            if(k==-1||p[j]==p[k])
            {
                j++;k++;
                if(p[j]!=p[k])Next[j]=k;
                else Next[j]=Next[k];
            }
            else k=Next[k];
        }
    }
    int kmp()
    {
        int j=0;
        int i=0;
        int count=0;
        while(j<plen&&i<slen)
        {
            if(j==-1||p[j]==s[i])
            {
                j++;i++;
            }
            else j=Next[j];
            if(j==plen)
            {
                j=0;
                count++;
            }
        }
        return count;
    }
    int main()
    {
        while(cin>>s&&s[0]!='#')
        {
            cin>>p;
            plen=p.size();
            slen=s.size();
            GetNext();
            printf("%d
    ",kmp());
        }
        return 0;
    } 
    View Code

     HDU 2594 Simpsons’ Hidden Talents (next函数应用)

    #include<iostream>
    #include<string.h>
    using namespace std;
    const int maxn=5e5+10;
    char s1[maxn],s2[maxn];
    int Next[maxn],len1,len2,ans;
    void GetNext()
    {
        int k=-1;
        int j=0;
        Next[0]=-1;
        while(j<len1+len2)
        {
            if(k==-1||s1[j]==s1[k])
            {
                j++;k++;Next[j]=k;
            }
            else k=Next[k];
        }
    }
    int main()
    {
        while(~scanf("%s%s",s1,s2))
        {
            len1=strlen(s1);
            len2=strlen(s2);
            strcat(s1,s2);
            GetNext();
            ans=Next[len1+len2];
            while(ans>len1||ans>len2)ans=Next[ans];
            if(ans){
                for(int i=0;i<ans;i++)printf("%c",s1[i]);printf(" %d",ans);printf("
    ");
            }
            else printf("%d
    ",ans);
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/Mingusu/p/11825769.html
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