https://www.cnblogs.com/wupeiqi/articles/5729934.html
https://www.cnblogs.com/wupeiqi/articles/5748496.html
MySQL测试题
一、表关系
请创建如下表,并创建相关约束
Microsoft Windows [版本 10.0.14393] (c) 2016 Microsoft Corporation。保留所有权利。 C:UsersAdministrator>mysql -u root -P3306 -h 127.0.0.1 ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: NO) C:UsersAdministrator>mysql -u root -P3306 -h 127.0.0.1 -p Enter password: ****** Welcome to the MySQL monitor. Commands end with ; or g. Your MySQL connection id is 2 Server version: 5.5.13 MySQL Community Server (GPL) Copyright (c) 2000, 2010, Oracle and/or its affiliates. All rights reserved. Oracle is a registered trademark of Oracle Corporation and/or its affiliates. Other names may be trademarks of their respective owners. Type 'help;' or 'h' for help. Type 'c' to clear the current input statement. mysql> show databases; +--------------------+ | Database | +--------------------+ | information_schema | | kaige | | mysql | | performance_schema | | runbs | | sdhz | | sunck | | test | +--------------------+ 8 rows in set (0.17 sec) mysql> create database sql_test -> ; Query OK, 1 row affected (0.07 sec) mysql> show databases; +--------------------+ | Database | +--------------------+ | information_schema | | kaige | | mysql | | performance_schema | | runbs | | sdhz | | sql_test | | sunck | | test | +--------------------+ 9 rows in set (0.00 sec) mysql> use sql_test; Database changed mysql> drop database sql_test; Query OK, 0 rows affected (0.21 sec) mysql> show databases; +--------------------+ | Database | +--------------------+ | information_schema | | kaige | | mysql | | performance_schema | | runbs | | sdhz | | sunck | | test | +--------------------+ 8 rows in set (0.00 sec) mysql> create database sql_test default charset utf-8 collate utf8_general_ci; ERROR 1115 (42000): Unknown character set: 'utf' mysql> create database sql_test default charset utf8 collate utf8_general_ci; Query OK, 1 row affected (0.00 sec) mysql> show databases; +--------------------+ | Database | +--------------------+ | information_schema | | kaige | | mysql | | performance_schema | | runbs | | sdhz | | sql_test | | sunck | | test | +--------------------+ 9 rows in set (0.00 sec) mysql> use sql_test; Database changed mysql> show tables; Empty set (0.05 sec) mysql> create table class( -> cid int not null auto_increment primary key, -> caption varchar(25) -> )engine=InnoDB DEFAULT CHARSET=utf8; Query OK, 0 rows affected (0.16 sec) mysql> show tables; +--------------------+ | Tables_in_sql_test | +--------------------+ | class | +--------------------+ 1 row in set (0.00 sec) mysql> desr class -> ; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'desr class' at line 1 mysql> desc class; +---------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------+-------------+------+-----+---------+----------------+ | cid | int(11) | NO | PRI | NULL | auto_increment | | caption | varchar(25) | YES | | NULL | | +---------+-------------+------+-----+---------+----------------+ 2 rows in set (0.09 sec) mysql> create table teacher( -> tid int auto_increment primary key not null, -> tname varchar(25), -> )engine=InnoDB default charset=utf8; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')engine=InnoDB default charset=utf8' at line 4 mysql> create table teacher( -> tid int auto_increment primary key not null, -> tname varchar(25) -> )engine=InnoDB default charset=utf8; Query OK, 0 rows affected (0.11 sec) mysql> desc teacher -> ; +-------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-------+-------------+------+-----+---------+----------------+ | tid | int(11) | NO | PRI | NULL | auto_increment | | tname | varchar(25) | YES | | NULL | | +-------+-------------+------+-----+---------+----------------+ 2 rows in set (0.01 sec) mysql> create table student( -> sid int auto_increment primary key not null, -> sname varchar(25), -> gender varchar(2), -> class_id int -> )engine=InnoDB default charset=utf8; Query OK, 0 rows affected (0.09 sec) mysql> alter table class add constraint FK_class_student foreign key class.cid references student.class_id; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'references student.class_id' at line 1 mysql> show tables; +--------------------+ | Tables_in_sql_test | +--------------------+ | class | | student | | teacher | +--------------------+ 3 rows in set (0.00 sec) mysql> desc student; +----------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +----------+-------------+------+-----+---------+----------------+ | sid | int(11) | NO | PRI | NULL | auto_increment | | sname | varchar(25) | YES | | NULL | | | gender | varchar(2) | YES | | NULL | | | class_id | int(11) | YES | | NULL | | +----------+-------------+------+-----+---------+----------------+ 4 rows in set (0.01 sec) mysql> desc class; +---------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------+-------------+------+-----+---------+----------------+ | cid | int(11) | NO | PRI | NULL | auto_increment | | caption | varchar(25) | YES | | NULL | | +---------+-------------+------+-----+---------+----------------+ 2 rows in set (0.01 sec) mysql> alter table student add constraint fk_stu_cls foreign key student(class_id) references class(cid); Query OK, 0 rows affected (0.38 sec) Records: 0 Duplicates: 0 Warnings: 0 mysql> desc student; +----------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +----------+-------------+------+-----+---------+----------------+ | sid | int(11) | NO | PRI | NULL | auto_increment | | sname | varchar(25) | YES | | NULL | | | gender | varchar(2) | YES | | NULL | | | class_id | int(11) | YES | MUL | NULL | | +----------+-------------+------+-----+---------+----------------+ 4 rows in set (0.00 sec) mysql> create table student( -> sid int not null primary key auto_increment, -> sname varchar(25), -> gender varchar(25), -> class_id;;;; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 5 ERROR: No query specified ERROR: No query specified ERROR: No query specified mysql> create table course9 -> create table course9;; -> -> ‘ -> ; -> -> ); ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'create table course9???? ?? ?? )' at line 2 mysql> create table course( -> cid int not null primary key auto_increment, -> cname varchar(25), -> tearch_id int -> )engine=InnoDB default charset=utf8; Query OK, 0 rows affected (0.09 sec) mysql> alter table course add constraint fk_cour_teach foreign key course(tearch_id) references teacher(tid); Query OK, 0 rows affected (0.16 sec) Records: 0 Duplicates: 0 Warnings: 0 mysql> create table score( -> sid int not null primary key auto_increment, -> student_id int not null, -> corse_id int not null, -> number int not null -> )engine=InnoDB default charset=utf8; Query OK, 0 rows affected (0.13 sec) mysql> alter table score add constraint score_to_stu foreign key score(student_id) references student(sid); Query OK, 0 rows affected (0.23 sec) Records: 0 Duplicates: 0 Warnings: 0 mysql> alter table score add constraint score_to_corse foreign key score(corse_id) references course(cid); Query OK, 0 rows affected (0.45 sec) Records: 0 Duplicates: 0 Warnings: 0 mysql>
mysql> select -> * -> from -> score -> left join student on score.student_id=student.sid -> left join course on score.corse_id=course.cid; +-----+------------+----------+--------+------+-------+--------+----------+------+---------+-----------+ | sid | student_id | corse_id | number | sid | sname | gender | class_id | cid | cname | tearch_id | +-----+------------+----------+--------+------+-------+--------+----------+------+---------+-----------+ | 1 | 1 | 1 | 60 | 1 | may | nv | 1 | 1 | shengwu | 1 | | 2 | 1 | 2 | 59 | 1 | may | nv | 1 | 2 | tiyu | 1 | | 3 | 2 | 2 | 100 | 2 | tom | na | 1 | 2 | tiyu | 1 | +-----+------------+----------+--------+------+-------+--------+----------+------+---------+-----------+ 3 rows in set (0.06 sec) mysql> select -> score.sid, -> score.student_id, -> student.sname, -> score.corse_id, -> course.cname, -> score.name -> from -> left join student on score.student_id=student.sid -> left join course on score.corse_id=course.cid; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'left join student on score.student_id=student.sid left join course on score.cors' at line 9 mysql> select -> score.sid, -> score.student_id, -> student.sname, -> score.corse_id, -> course.cname, -> score.number -> from -> left join student on score.student_id=student.sid -> left join course on score.corse_id=course.cid; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'left join student on score.student_id=student.sid left join course on score.cors' at line 9 mysql> select score.sid,score.student_id,student.sname,score.corse_id,course.cname,score.number from -> left join student on score.student_id=student.sid leftjoin course on course.cid=score.corse_id; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'left join student on score.student_id=student.sid leftjoin course on course.cid=' at line 2 mysql> select * from -> left join student on score.student_id=student.sid leftjoin course on course.cid=score.corse_id; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'left join student on score.student_id=student.sid leftjoin course on course.cid=' at line 2 mysql>
mysql> select * from -> score -> left join student on score.student_id=student.sid -> left join course on score.corse_id=course.cid; +-----+------------+----------+--------+------+-------+--------+----------+------+---------+-----------+ | sid | student_id | corse_id | number | sid | sname | gender | class_id | cid | cname | tearch_id | +-----+------------+----------+--------+------+-------+--------+----------+------+---------+-----------+ | 1 | 1 | 1 | 60 | 1 | may | nv | 1 | 1 | shengwu | 1 | | 2 | 1 | 2 | 59 | 1 | may | nv | 1 | 2 | tiyu | 1 | | 3 | 2 | 2 | 100 | 2 | tom | na | 1 | 2 | tiyu | 1 | +-----+------------+----------+--------+------+-------+--------+----------+------+---------+-----------+ 3 rows in set (0.00 sec) mysql> select -> score.sid, -> score.student_id, -> student.sname, -> score.corse_id, -> course.cname, -> score.number -> from score -> left join student on score.student_id=student.sid -> left join course on score.corse_id=course.cid; +-----+------------+-------+----------+---------+--------+ | sid | student_id | sname | corse_id | cname | number | +-----+------------+-------+----------+---------+--------+ | 1 | 1 | may | 1 | shengwu | 60 | | 2 | 1 | may | 2 | tiyu | 59 | | 3 | 2 | tom | 2 | tiyu | 100 | +-----+------------+-------+----------+---------+--------+ 3 rows in set (0.00 sec) mysql>
二、操作表
1、自行创建测试数据
2、查询“生物”课程比“物理”课程成绩高的所有学生的学号;
3、查询平均成绩大于60分的同学的学号和平均成绩;
-- SELECT MAX(cid) FROM class; -- SELECT sum(cid) FROM class; -- SELECT AVG(cid) FROM class; -- SELECT COUNT(cid) FROM class; -- SELECT sum(cid)/COUNT(cid) FROM class; -- -- SELECT student_id,AVG(num) FROM score GROUP BY student_id HAVING avg(num)>60; SELECT student_id,student.sname,AVG(num) FROM score left JOIN student ON student.sid=score.student_id GROUP BY student_id HAVING avg(num)>60 ;
-- SELECT MAX(cid) FROM class; -- SELECT sum(cid) FROM class; -- SELECT AVG(cid) FROM class; -- SELECT COUNT(cid) FROM class; -- SELECT sum(cid)/COUNT(cid) FROM class; -- -- SELECT student_id,AVG(num) FROM score GROUP BY student_id HAVING avg(num)>60; -- SELECT student_id,student.sname,AVG(num) FROM score left JOIN student ON student.sid=score.student_id GROUP BY student_id HAVING avg(num)>60 ; SELECT t.student_id,t.a,student.sname from (SELECT student_id,AVG(num)as a FROM score GROUP BY student_id HAVING avg(num)>60 )as t LEFT JOIN student on t.student_id=student.sid;
4、查询所有同学的学号、姓名、选课数、总成绩;
5、查询姓“李”的老师的个数;
-- SELECT * from teacher WHERE tname like "李%"; -- SELECT COUNT(tid) from teacher WHERE tname like "李%"; -- SELECT tid,tname,"ok" from teacher WHERE tname like "李%"; SELECT COUNT("ok") FROM (SELECT tid,tname,"ok" from teacher WHERE tname like "李%") as v
6、查询没学过“叶平”老师课的同学的学号、姓名;
7、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名;
-- SELECT * from score WHERE score.course_id=1 or score.course_id=2; -- SELECT B.student_id,COUNT(B.student_id) FROM (SELECT student_id,course_id from score WHERE score.course_id=1 or score.course_id=2)as B GROUP BY B.student_id HAVING COUNT(B.student_id)>1; SELECT BB.student_id,student.sname FROM(SELECT B.student_id,COUNT(B.student_id) FROM (SELECT student_id,course_id from score WHERE score.course_id=1 or score.course_id=2)as B GROUP BY B.student_id HAVING COUNT(B.student_id)>1) as BB JOIN student ON student.sid=BB.student_id;
8、查询学过“李平”老师所教的所有课的同学的学号、姓名;
-- 拿到李平老师教的所有课程 -- SELECT * from course LEFT JOIN teacher ON course.teacher_id=teacher.tid WHERE teacher.tname="李平老师"; -- SELECT * FROM (SELECT student_id FROM score WHERE course_id in ( -- SELECT cid from course LEFT JOIN teacher ON course.teacher_id=teacher.tid WHERE teacher.tname="李平老师" -- ))as TT LEFT JOIN student on TT.student_id=student.sid GROUP BY TT.student_id; SELECT student_id FROM score WHERE course_id in ( SELECT cid from course LEFT JOIN teacher ON course.teacher_id=teacher.tid WHERE teacher.tname="李平老师" )
9、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名;
10、查询有课程成绩小于60分的同学的学号、姓名;
-- 查询有课程成绩小于60分的同学的学号、姓名 -- SELECT score.student_id from score WHERE num<60 GROUP BY score.student_id -- SELECT student.sid,student.sname FROM (SELECT score.student_id from score WHERE num<60 GROUP BY score.student_id -- )as S LEFT JOIN student ON student.sid=S.student_id
11、查询没有学全所有课的同学的学号、姓名;
-- 去重 -- SELECT DISTINCT student_id FROM score WHERE num<60; -- 查询没有学全所有课的同学的学号、姓名; -- SELECT student_id,COUNT(1) from score GROUP BY student_id HAVING COUNT(student_id)<(SELECT COUNT(1)as c FROM course) -- SELECT COUNT(1)as c FROM course SELECT A.student_id,student.sname from (SELECT student_id,COUNT(1) from score GROUP BY student_id HAVING COUNT(student_id)<(SELECT COUNT(1)as c FROM course))as A LEFT JOIN student ON student.sid=A.student_id;
12、查询至少有一门课与学号为“001”的同学所学相同的同学的学号和姓名;
-- 查询至少有一门课与学号为“001”的同学所学相同的同学的学号和姓名; SELECT * FROM student WHERE student.sid IN (SELECT student_id from score WHERE student_id!=1 AND course_id in ( SELECT course_id FROM score WHERE score.student_id=1 )GROUP BY student_id)
13、查询至少学过学号为“001”同学所选课程中任意一门课的其他同学学号和姓名;
14、查询和“002”号的同学学习的课程完全相同的其他同学学号和姓名;
-- 查询和“001”号的同学学习的课程完全相同的其他同学学号和姓名; SELECT student_id,COUNT(student_id) FROM score WHERE course_id IN (SELECT course_id from score WHERE score.student_id=1) GROUP BY student_id HAVING COUNT(student_id)=(SELECT COUNT(1) from score WHERE score.student_id=1)
15、删除学习“叶平”老师课的SC表记录;
16、向SC表中插入一些记录,这些记录要求符合以下条件:①没有上过编号“002”课程的同学学号;②插入“002”号课程的平均成绩;
17、按平均成绩从低到高显示所有学生的“语文”、“数学”、“英语”三门的课程成绩,按如下形式显示: 学生ID,语文,数学,英语,有效课程数,有效平均分;
SELECT student_id, num, (SELECT num from score as innerTb where innerTb.student_id=outerTb.student_id and course_id=1)as yw, (SELECT num from score as innerTb where innerTb.student_id=outerTb.student_id and course_id=2)as wl, (SELECT num from score as innerTb where innerTb.student_id=outerTb.student_id and course_id=3)as ty, AVG(num), COUNT(student_id) from score as outerTb GROUP BY student_id;
18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分;
-- 查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分; -- SELECT course.cid, -- (SELECT MAX(num) FROM score WHERE score.course_id=course.cid), -- (SELECT min(num) FROM score WHERE score.course_id=course.cid) -- from course; SELECT course_id ,MAX(num),MIN(num)from score GROUP BY course_id;
19、按各科平均成绩从低到高和及格率的百分数从高到低顺序;
-- 按各科平均成绩从低到高和及格率的百分数从高到低顺序; -- SELECT * from score; -- SELECT AVG(num) FROM score GROUP BY student_id desc ; SELECT course_id,MAX(num),MIN(num),AVG(num),COUNT(course_id),SUM(CASE WHEN score.num>60 then 1 ELSE 0 END),SUM(CASE WHEN score.num>60 then 1 ELSE 0 END)/COUNT(course_id)*100 FROM score GROUP BY course_id;
20、课程平均分从高到低显示(显示任课老师);
-- 课程平均分从高到低显示(现实任课老师) SELECT course_id,AVG(num)as aa from score GROUP BY course_id ORDER BY aa DESC;
SELECT aa,ee.course_id,course.teacher_id,teacher.tname from (SELECT score.course_id,AVG(num)as aa from score GROUP BY course_id DESC ORDER BY aa desc)as ee LEFT JOIN course on course.teacher_id=ee.course_id left JOIN teacher on teacher.tid=course.teacher_id;
21、查询各科成绩前三名的记录:(不考虑成绩并列情况)
-- 查询各科成绩前三名的记录:(不考虑成绩并列情况) -- SELECT *,(SELECT num FROM score as s2 WHERE s2.course_id=s1.course_id ORDER BY num LIMIT 0,1 ) as fist_num FROM score as s1; SELECT * FROM( SELECT *, (SELECT num from score as s2 where s2.course_id=s1.course_id ORDER BY num DESC LIMIT 0,1) as fist_num , (SELECT num from score as s2 where s2.course_id=s1.course_id ORDER BY num DESC LIMIT 2,1) as third_num from score as s1 )AS T WHERE num>=third_num AND num<=fist_num;
22、查询每门课程被选修的学生数;
-- 查询每门课程被选修的学生数; -- SELECT student_id,COUNT(course_id) FROM score GROUP BY student_id SELECT score.course_id,COUNT(student_id) from score GROUP BY score.course_id
23、查询出只选修了一门课程的全部学生的学号和姓名;
-- 查询出只选修了一门课程的全部学生的学号和姓名; -- SELECT * from ( -- SELECT student_id ,COUNT(1) as aa FROM score GROUP BY student_id -- ) as T -- LEFT JOIN student ON student.sid=T.student_id -- WHERE T.aa=1; SELECT student_id ,COUNT(1) as aa FROM score GROUP BY student_id HAVING aa=1
24、查询男生、女生的人数;
-- 查询男生、女生的人数; -- SELECT gender ,COUNT(1),"男","女" from student GROUP BY gender SELECT (SELECT COUNT(1) FROM student WHERE gender="男")as "男", (SELECT COUNT(1) FROM student WHERE gender="女")as "女"
25、查询姓“张”的学生名单;
SELECT * FROM student WHERE sname LIKE "张%"
26、查询同名同姓学生名单,并统计同名人数;
1 SELECT sid,sname,COUNT(1)as "数量" FROM student GROUP BY sname;
27、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列;
-- 查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列;
SELECT course_id,AVG(num)as aa FROM score GROUP BY course_id ORDER by aa ASC ,course_id DESC;
28、查询平均成绩大于85的所有学生的学号、姓名和平均成绩;
29、查询课程名称为“数学”,且分数低于60的学生姓名和分数;
30、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名;
31、求选了课程的学生人数
32、查询选修“杨艳”老师所授课程的学生中,成绩最高的学生姓名及其成绩;
33、查询各个课程及相应的选修人数;
34、查询不同课程但成绩相同的学生的学号、课程号、学生成绩;
35、查询每门课程成绩最好的前两名;
36、检索至少选修两门课程的学生学号;
37、查询全部学生都选修的课程的课程号和课程名;
38、查询没学过“叶平”老师讲授的任一门课程的学生姓名;
39、查询两门以上不及格课程的同学的学号及其平均成绩;
40、检索“004”课程分数小于60,按分数降序排列的同学学号;
41、删除“002”同学的“001”课程的成绩;
-- SELECT MAX(cid) FROM class; -- SELECT sum(cid) FROM class; -- SELECT AVG(cid) FROM class; -- SELECT COUNT(cid) FROM class; -- SELECT sum(cid)/COUNT(cid) FROM class; -- -- SELECT student_id,AVG(num) FROM score GROUP BY student_id HAVING avg(num)>60; -- SELECT student_id,student.sname,AVG(num) FROM score left JOIN student ON student.sid=score.student_id GROUP BY student_id HAVING avg(num)>60 ; -- SELECT t.student_id,t.a,student.sname from (SELECT student_id,AVG(num)as a FROM score GROUP BY student_id HAVING avg(num)>60 )as t LEFT JOIN student on t.student_id=student.sid; -- SELECT * from teacher WHERE tname like "李%"; -- SELECT COUNT(tid) from teacher WHERE tname like "李%"; -- SELECT tid,tname,"ok" from teacher WHERE tname like "李%"; -- SELECT COUNT("ok") FROM (SELECT tid,tname,"ok" from teacher WHERE tname like "李%") as v -- SELECT * from score WHERE score.course_id=1 or score.course_id=2; -- SELECT B.student_id,COUNT(B.student_id) FROM (SELECT student_id,course_id from score WHERE score.course_id=1 or score.course_id=2)as B GROUP BY B.student_id HAVING COUNT(B.student_id)>1; -- SELECT BB.student_id,student.sname FROM(SELECT B.student_id,COUNT(B.student_id) FROM (SELECT student_id,course_id from score WHERE score.course_id=1 or score.course_id=2)as B GROUP BY B.student_id HAVING COUNT(B.student_id)>1) -- as BB JOIN student ON student.sid=BB.student_id; -- 拿到李平老师教的所有课程 -- SELECT * from course LEFT JOIN teacher ON course.teacher_id=teacher.tid WHERE teacher.tname="李平老师"; -- SELECT * FROM (SELECT student_id FROM score WHERE course_id in ( -- SELECT cid from course LEFT JOIN teacher ON course.teacher_id=teacher.tid WHERE teacher.tname="李平老师" -- ))as TT LEFT JOIN student on TT.student_id=student.sid GROUP BY TT.student_id; -- SELECT student_id FROM score WHERE course_id in ( -- SELECT cid from course LEFT JOIN teacher ON course.teacher_id=teacher.tid WHERE teacher.tname="李平老师" -- )GROUP BY student_id -- 查询有课程成绩小于60分的同学的学号、姓名 -- SELECT score.student_id from score WHERE num<60 GROUP BY score.student_id -- SELECT student.sid,student.sname FROM (SELECT score.student_id from score WHERE num<60 GROUP BY score.student_id -- )as S LEFT JOIN student ON student.sid=S.student_id -- 去重 -- SELECT DISTINCT student_id FROM score WHERE num<60; -- 查询没有学全所有课的同学的学号、姓名; -- SELECT student_id,COUNT(1) from score GROUP BY student_id HAVING COUNT(student_id)<(SELECT COUNT(1)as c FROM course) -- SELECT COUNT(1)as c FROM course -- SELECT A.student_id,student.sname from (SELECT student_id,COUNT(1) from score GROUP BY student_id HAVING COUNT(student_id)<(SELECT COUNT(1)as c FROM course))as A LEFT JOIN student ON student.sid=A.student_id; -- 查询至少有一门课与学号为“001”的同学所学相同的同学的学号和姓名; -- SELECT * FROM student WHERE student.sid IN -- (SELECT student_id from score WHERE student_id!=1 AND course_id in ( -- SELECT course_id FROM score WHERE score.student_id=1 -- )GROUP BY student_id) -- 查询和“001”号的同学学习的课程完全相同的其他同学学号和姓名; -- SELECT student_id,COUNT(student_id) FROM score WHERE course_id IN -- (SELECT course_id from score WHERE score.student_id=1) GROUP BY student_id -- HAVING COUNT(student_id)=(SELECT COUNT(1) from score WHERE score.student_id=1) -- -- 与2号学生选择个数一样的同学 -- SELECT student_id,COUNT(student_id) from score GROUP BY score.student_id -- HAVING COUNT(student_id)=( -- SELECT COUNT(1) as a from score WHERE student_id=2 -- ) SELECT student_id,COUNT(student_id) from score GROUP BY score.student_id HAVING COUNT(student_id)=( SELECT COUNT(1) as a from score WHERE student_id=2 )