1.情景展示
如何根据身份证号，计算出出生日期、性别、年龄?
2.解决方案
从网上找的别人的，因为并没有实际用到，所以并未对其优化！
/**
* 通过身份证号码获取出生日期、性别、年龄
* @param certificateNo
* @return 返回的出生日期格式：1990-01-01 性别格式：F-女，M-男
*/
public static Map<String, String> getBirAgeSex(String certificateNo) {
String birthday = "";
String age = "";
String sexCode = "";
int year = Calendar.getInstance().get(Calendar.YEAR);
char[] number = certificateNo.toCharArray();
boolean flag = true;
if (number.length == 15) {
for (int x = 0; x < number.length; x++) {
if (!flag)
return new HashMap<String, String>();
flag = Character.isDigit(number[x]);
}
} else if (number.length == 18) {
for (int x = 0; x < number.length - 1; x++) {
if (!flag)
return new HashMap<String, String>();
flag = Character.isDigit(number[x]);
}
}
if (flag && certificateNo.length() == 15) {
birthday = "19" + certificateNo.substring(6, 8) + "-" + certificateNo.substring(8, 10) + "-"
+ certificateNo.substring(10, 12);
sexCode = Integer.parseInt(certificateNo.substring(certificateNo.length() - 3, certificateNo.length()))
% 2 == 0 ? "F" : "M";
age = (year - Integer.parseInt("19" + certificateNo.substring(6, 8))) + "";
} else if (flag && certificateNo.length() == 18) {
birthday = certificateNo.substring(6, 10) + "-" + certificateNo.substring(10, 12) + "-"
+ certificateNo.substring(12, 14);
sexCode = Integer.parseInt(certificateNo.substring(certificateNo.length() - 4, certificateNo.length() - 1))
% 2 == 0 ? "F" : "M";
age = (year - Integer.parseInt(certificateNo.substring(6, 10))) + "";
}
Map<String, String> map = new HashMap<String, String>();
map.put("birthday", birthday);
map.put("age", age);
map.put("sexCode", sexCode);
return map;
}
根据身份证号提取出生日期
// 出生日期
String birthday = "";
// 身份证号不为空
if (sfzh.length() == 15) {
birthday = "19" + sfzh.substring(6, 8) + "-" + sfzh.substring(8, 10) + "-" + sfzh.substring(10, 12);
} else if (sfzh.length() == 18) {
birthday = sfzh.substring(6, 10) + "-" + sfzh.substring(10, 12) + "-" + sfzh.substring(12, 14);
}