• C语言 aabbcc、abc、fabc、aabc


    输入一个字符串,匹配字符串中连续出现的字符串、并且连续个数相等

    如输入 aabbcc、abc、fabc、aabc、aabbc

    分别输出yes还是no

    #include<stdio.h>
    #include<string.h>
    void main()
    {
    /*
    思路:输入一个字符串数组a,定义一个数组b[3]={1,0,0}(其用意是默认第一个是不需要匹配的)

    */
    char a[]={'f','a','a','a','b','d','c'};

    int b[3]={1,0,0};
    int i = 0;
    int f = 0;
    int g = 0;
    int h = 1;
    printf("a===%d ",sizeof(a));
    for( i = 1 ; i< sizeof(a);i++)
    {
    printf("i====%d ",i);
    //如果a[i-1] == a[i],默认从a[0] == a[1]开始,相等就加一,相当于a[0]='a' == a[1]='a'
    if(a[i-1] == a[i]){
    b[g] = ++h;
    printf("b[%d]=%d ",g,b[g]);
    }
    //此处只需要判断不相等
    if((a[i-1] != a[i]) && (a[i-1]-a[i] == -1)){//&& a[i]-a[i+1] = 1
    if( a[i-1]-a[i] == -1){
    h = 1;
    g = g+1;
    b[g] = h;
    }else{
    if(g==0){
    b[0] = 1;
    b[1] = 0;
    b[2] = 0;
    }
    if(g == 1){
    b[0] = b[1];
    b[1] = 0;
    b[2] = 0;
    }
    if(g == 2){
    b[0] = b[2];
    b[1] = 0;
    b[2] = 0;
    }

    h = 1;
    g = 0;
    }
    }
    printf("%d ",b[0]);
    printf("%d ",b[1]);
    printf("%d ",b[2]);
    printf("----------------------------- ");
    if(b[0] >= b[1] && b[1]== b[2] && b[2]>=1){
    printf("yes ");
    break;
    }

    }

    }

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  • 原文地址:https://www.cnblogs.com/M-D-Luffy/p/4039305.html
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