• HDU4477 Cut the rope II 递推


    题意:转化后为给定一个数L,问L拆成N个不同的数相加的方案数,其中N>=2。

    解法:其实和上次做的分解的2的幂的数量相同,由于要求每个数都不相同,这里有一个非常好的观察角度,那就是观察一个数的分解中是否存在1,再加上考虑其能够被分解的数的个数即可建立递推关系。

    设f[i][j]表示数 i 被分成 j 个不同的数相加的方案数,那么考虑最后分解中不含有1,那么这部分由f[i-j][j]得到,因为后者的每一个分解出来的数都加上1就行了;接着考虑分解中含有1,那么可以假定这个1就是最后分出来的,因为分解的顺序并不影响最后的结果,由于分解中数均不相同,扣除1后,就变成了f[i-1][j-1]中不含有1的情况了,而这个结果就又可以转化为:f[i-1-(j-1)][j-1]了。整个过程非常的巧妙。一个数最多分解成多少个数相加呢?这里可以假设L被连续的1+2+...+N组成,能够推算出一个上界出来。即求一个最大的x满足x*(x+1)/2 <= L。

    直接开设状态会导致TLE,由于之多只和前300来层有关系,因此来个350的第一维来滚动吧。看到另外一种压缩方法是把第二维变成01,看来两者结合起来可以使得使用内存更加小。

    代码如下:

    #include <cstdlib>
    #include <cstring>
    #include <cstdio>
    #include <iostream>
    #include <algorithm>
    #include <cmath>
    using namespace std;
    
    int f[350][350]; // 50000的长度也最多拆成满足等式 x*(x+1)/2<=50000 的最大的x段 
    // 这题和上次的一道拆分成2的幂的题目非常的像了,从一个拆分中是否有1这个元素进行递推 
    int ans[50005];
    const int MOD = 1000000;
    
    int get(int x) {
        int k = (int)sqrt(2.0*x);
        while ((k+1)*(k+2)/2 <= x) k++;
        while (k*(k+1)/2 > x) k--;
        // 准确的计算出最多由多少个元素组成
        return k;
    }
    
    void pre() {
        for (int cur = 0, i = 3; i <= 50000; ++i, cur = (cur+1) % 350) {
            int k = get(i);
            f[cur][2] = (i - 1) >> 1;
            ans[i] = f[cur][2];
            for (int j = 3; j <= k; ++j) { // 至少由两部分组成
                int nxt = (cur - j + 350) % 350;
                f[cur][j] = (f[nxt][j] + f[nxt][j-1]) % MOD;
                // 这个式子的含义是从不含1和含1两个状态合并并等价而来 
                ans[i] = (ans[i] + f[cur][j]) % MOD;
            }
        }
    }
    
    int main() {
        int T, N;
        pre();
        scanf("%d", &T);
        while (T--) {
            scanf("%d", &N);
            printf("%d\n", ans[N]);
        }
        return 0;
    }

    附(未取模):

    i = 2, ret = 0
    i = 3, ret = 1
    i = 4, ret = 1
    i = 5, ret = 2
    i = 6, ret = 3
    i = 7, ret = 4
    i = 8, ret = 5
    i = 9, ret = 7
    i = 10, ret = 9
    i = 11, ret = 11
    i = 12, ret = 14
    i = 13, ret = 17
    i = 14, ret = 21
    i = 15, ret = 26
    i = 16, ret = 31
    i = 17, ret = 37
    i = 18, ret = 45
    i = 19, ret = 53
    i = 20, ret = 63
    i = 21, ret = 75
    i = 22, ret = 88
    i = 23, ret = 103
    i = 24, ret = 121
    i = 25, ret = 141
    i = 26, ret = 164
    i = 27, ret = 191
    i = 28, ret = 221
    i = 29, ret = 255
    i = 30, ret = 295
    i = 31, ret = 339
    i = 32, ret = 389
    i = 33, ret = 447
    i = 34, ret = 511
    i = 35, ret = 584
    i = 36, ret = 667
    i = 37, ret = 759
    i = 38, ret = 863
    i = 39, ret = 981
    i = 40, ret = 1112
    i = 41, ret = 1259
    i = 42, ret = 1425
    i = 43, ret = 1609
    i = 44, ret = 1815
    i = 45, ret = 2047
    i = 46, ret = 2303
    i = 47, ret = 2589
    i = 48, ret = 2909
    i = 49, ret = 3263
    i = 50, ret = 3657
    i = 51, ret = 4096
    i = 52, ret = 4581
    i = 53, ret = 5119
    i = 54, ret = 5717
    i = 55, ret = 6377
    i = 56, ret = 7107
    i = 57, ret = 7916
    i = 58, ret = 8807
    i = 59, ret = 9791
    i = 60, ret = 10879
    i = 61, ret = 12075
    i = 62, ret = 13393
    i = 63, ret = 14847
    i = 64, ret = 16443
    i = 65, ret = 18199
    i = 66, ret = 20131
    i = 67, ret = 22249
    i = 68, ret = 24575
    i = 69, ret = 27129
    i = 70, ret = 29926
    i = 71, ret = 32991
    i = 72, ret = 36351
    i = 73, ret = 40025
    i = 74, ret = 44045
    i = 75, ret = 48445
    i = 76, ret = 53249
    i = 77, ret = 58498
    i = 78, ret = 64233
    i = 79, ret = 70487
    i = 80, ret = 77311
    i = 81, ret = 84755
    i = 82, ret = 92863
    i = 83, ret = 101697
    i = 84, ret = 111321
    i = 85, ret = 121791
    i = 86, ret = 133183
    i = 87, ret = 145577
    i = 88, ret = 159045
    i = 89, ret = 173681
    i = 90, ret = 189585
    i = 91, ret = 206847
    i = 92, ret = 225584
    i = 93, ret = 245919
    i = 94, ret = 267967
    i = 95, ret = 291873
    i = 96, ret = 317787
    i = 97, ret = 345855
    i = 98, ret = 376255
    i = 99, ret = 409173
    i = 100, ret = 444792
    i = 101, ret = 483329
    i = 102, ret = 525015
    i = 103, ret = 570077
    i = 104, ret = 618783
    i = 105, ret = 671417
    i = 106, ret = 728259
    i = 107, ret = 789639
    i = 108, ret = 855905
    i = 109, ret = 927405
    i = 110, ret = 1004543
    i = 111, ret = 1087743
    i = 112, ret = 1177437
    i = 113, ret = 1274117
    i = 114, ret = 1378303
    i = 115, ret = 1490527
    i = 116, ret = 1611387
    i = 117, ret = 1741520
    i = 118, ret = 1881577
    i = 119, ret = 2032289
    i = 120, ret = 2194431
    i = 121, ret = 2368799
    i = 122, ret = 2556283
    i = 123, ret = 2757825
    i = 124, ret = 2974399
    i = 125, ret = 3207085
    i = 126, ret = 3457026
    i = 127, ret = 3725409
    i = 128, ret = 4013543
    i = 129, ret = 4322815
    i = 130, ret = 4654669
    i = 131, ret = 5010687
    i = 132, ret = 5392549
    i = 133, ret = 5802007
    i = 134, ret = 6240973
    i = 135, ret = 6711479
    i = 136, ret = 7215643
    i = 137, ret = 7755775
    i = 138, ret = 8334325
    i = 139, ret = 8953855
    i = 140, ret = 9617149
    i = 141, ret = 10327155

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  • 原文地址:https://www.cnblogs.com/Lyush/p/3110902.html
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