POJ2034 Antiprime Sequences dfs

筛出素数然后直接暴力即可。

代码如下：

#include <cstdlib>
#include <cstring>
#include <cstdio>
#define MAXN 10000
using namespace std;

int N, M, d, p[600005];
int hash[10005], path[10005];

void pre()
{
    int k;
    for (int i = 4; i <= MAXN; i += 2) {
        p[i] = 1;
    }    
    for (int i = 3; i <= 105; i += 2) {
        if (!p[i]) {
            k = 2 * i;     
            for (int j = i * i; j <= MAXN; j += k) {
                p[j] = 1;
            }
        }
    }
}

bool dfs(int x, int step)
{
    path[step] = x;
    if (step >= 2) { 
        int sum = path[step], k = step > d ? d : step;
        for (int i = step-1; i > step-k; --i) {
            sum += path[i];
            if (!p[sum]) {
                return false;
            }
        }
        if (step == M-N+1) {
            for (int i = 1; i <= M-N+1; ++i) {
                printf(i == 1 ? "%d" : ",%d", path[i]);
            }
            puts("");
            return true;
        }
    }
    for (int i = N; i <= M; ++i) {
        if (!hash[i]) {
            hash[i] = 1;
            if (dfs(i, step + 1)) {
                return true;
            }
            hash[i] = 0;
        }
    }
    return false;
}

int main()
{
    int flag;
    pre(); 
    while (scanf("%d %d %d", &N, &M, &d), N|M|d) {
        if (N > M) {
            int t = N; 
            N = M;
            M = t;
        }
        flag = 0;
        memset(hash, 0, sizeof (hash));
        for (int i = N; i <= M; ++i) {
            hash[i] = 1;
            if (dfs(i, 1)) {
                flag = 1;
                break;
            }
            hash[i] = 0;
        }
        if (!flag) {
            puts("No anti-prime sequence exists.");
        }
    }
    return 0;    
}