Happy Number
Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example: 19 is a happy number
- 1^2 + 9^2 = 82
- 8^2 + 2^2 = 68
- 6^2 + 8^2 = 100
- 1^2 + 0^2 + 0^2 = 1
https://leetcode.com/problems/happy-number/
累加每一位数字的平方数,如果等于1就是happy number,否则递归去找,遇到死循环说明不是。
常规思路是开个哈希表,记录已经出现的数,一遇到重复就返回false。
使用带哈希表的代码,把个位数打个表,发现只有1和7是happy number,其他都不是。
那么为了去掉哈希表,我直接写死了1-9的结果,因为happy number的运算很多中间结果都是个位数,遇到个位数就可以不用做下去了。
1 /** 2 * @param {number} n 3 * @return {boolean} 4 */ 5 var isHappy = function(n) { 6 if(n === 1 || n === 7) return true; 7 if(n < 10) return false; 8 n = n.toString(); 9 var nextNum = 0, tmp; 10 for(var i = 0; i < n.length; i++){ 11 tmp = Math.floor(n[i]); 12 nextNum += tmp * tmp; 13 } 14 return isHappy(nextNum); 15 };