• java中json的使用和解析


    1.创建json对象

    1.1 创建JSONObject对象

    使用map初始化json

        @Test
        public void test1() 
        {    
            Map<String, Object> map = new LinkedHashMap<String, Object>();
            map.put("name", "孙笑川");
            map.put("age", 25);
            map.put("height", 1.70);
            map.put("major", new String[] { "理发", "挖掘机" });
            map.put("hasGirlFriend", false);
            map.put("car", null);
            map.put("house", null);
            
            //null作为value时,转换成json后不会保存
            JSONObject json1 = new JSONObject(map);    
            System.out.println(json1.toString());
            Map map2 = json1.toMap();
            System.out.println(map2.toString());
        }

    可以看到,当value为null时,转化为json后不会保存,会直接抛弃。

      

    使用javabean初始化json

    //javaBean
    class Person {
        public String name;
        public int age;
        public String idCard;
             //省略getter&setter
                    }    
    
    //使用javaBean初始化json
        @Test
        public void test2() 
        {
            Person person = new Person();
            person.setName("孙亚龙");
            person.setAge(30);
            person.setIdCard("512445546565164641212");
            
            JSONObject json2 = new JSONObject(person);
            
            System.out.println(json2.toString());
        }

    直接创建JSONObject 

        @Test
        public void test3() 
        {
            JSONObject json3 = new JSONObject();
            Object nullObj = null;
            
            json3.put("name", "孙悟空");
            json3.put("changeTimes", 72);
            json3.put("name", "MonkeySun"); //put方法:value保留原格式,若key相等,value会覆盖原值
            json3.put("isHuman", false);    
             
            json3.append("nickName", "齐天大圣"); //append方法:value存放在数组中,若key相等,value会覆盖原值
            json3.append("nickName", "弼马温");
            
            json3.accumulate("Teacher", "元始天尊"); //accmulate方法,和append方法一样
            json3.accumulate("Teacher", "唐三藏");
            
            
            System.out.println(json3.toString());
        }

     

    1.2 创建JSONArray对象

    直接从字符串获取:

      用给定的字符串初始化JSONArray对象,字符串最外层必须为中括号包裹:

        @Test
        public void test12() 
        {
            String jsonString = "['white','卢本伟','芦苇','卢姥爷']";
            
            JSONArray jsonArray = new JSONArray(jsonString);
            for (Object object : jsonArray) {
                System.out.println(object);
            }
        }

    直接创建JSONArray对象:

      创建一个空的JSONArray对象,使用put传值

        @Test
        public void test_1() 
        {
            JSONArray jsonArray = new JSONArray();
            //1.put(value)方法 
            jsonArray.put("孙悟空");
            //2.put(index value)方法
            jsonArray.put(1,"{'变化':72,'武器',金箍棒}");
            
            System.out.println(jsonArray);
        }

    2.解析json

    2.1 官方json包解析

      使用官方json包解析时,需要下载json官方jar包,并导入

      下载地址(maven仓库):https://mvnrepository.com/artifact/org.json/json/20180813

      导入jar包:

    import org.json.JSONArray;
    import org.json.JSONObject;
    • 待解析的字符串是简单对象类型,大括号 { }包围时:
          @Test
          public void test6() 
          {
              //待解析的json字符串
              String jsonString = "{'name':'卢本伟','age':24,'Position':'Mid'}";
              
              //因为json字符串是大括号包围,所以用JSONObject解析
              JSONObject json = new JSONObject(jsonString);    
      
              String name = json.getString("name");
              int age = json.getInt("age");
              String position = json.getString("Position");
              System.out.println("姓名:"+name);
              System.out.println("年龄:"+age);
              System.out.println("位置"+position);                
          }

    • 待解析的字符串是数组类型,被中括号 [  ]  包围时:
        @Test
        public void test7() 
        {
            //待解析的json字符串
            String jsonString = "['卢本伟','white','卢伟','五五开']";
            
            //因为json字符串是大括号包围,所以用JSONArray解析
            JSONArray jsonArray = new JSONArray(jsonString);
            
            //遍历即可,foreach或for循环
            for (Object name : jsonArray) {
                System.out.println(name);
            }
        }

    • 待解析的字符串既有中括号 [  ]、又有大括号[  ] 包围时,逐层解析
    @Test
        public void test5() 
        {
            //待解析的json字符串
            String jsonString = "{'name':'卢本伟','age':24,'Hero':{'name':'Fizz','Position':'Mid','charactor':'killer'},'nickNames':['五五开','芦苇','white'],'Honors':[{'year':2011,'name':'TGA总决赛冠军'},{'year':2013,'name':'S3全球总决赛中国区冠军'},{'year':2013,'name':'S3全球总决赛亚军'}]}";
            
            try {
            //因为json字符串是大括号包围,所以用JSONObject解析
            JSONObject json = new JSONObject(jsonString);
            
            /*
             * 普通元素,根据类型直接获取
             */
            String name = json.getString("name");
            int age = json.getInt("age");
            System.out.println("姓名:"+name);
            System.out.println("年龄:"+age);
            System.out.println("————————————————————————————————");
            
            /*
             * 属性大括号包括,先获取JSONObject对象
             */
            JSONObject hero = json.getJSONObject("Hero");
            String hero_name = hero.getString("name");
            String hero_position = hero.getString("Position");
            String hero_charactor = hero.getString("charactor");
            System.out.println("擅长英雄:");
            System.out.println("英雄名:"+hero_name);
            System.out.println("位置:"+hero_position);
            System.out.println("英雄定位:"+hero_charactor);
            System.out.println("————————————————————————————————");
            
            /*
             * 属性被中括号包括,获取JSONArray对象,遍历即可
             */
            System.out.println("外号:");
            JSONArray nickNames = json.getJSONArray("nickNames");
            for (Object nickName : nickNames) {
                System.out.println(nickName);
            }
            System.out.println("————————————————————————————————");
            
            /*
             * 属性中既有中括号包括,又嵌套了大括号,一层层获取即可
             */
            JSONArray Honors = json.getJSONArray("Honors");
            System.out.println("所获荣誉:");
            for(int i=0;i<Honors.length();i++) 
            {
                JSONObject honor = Honors.getJSONObject(i);
                int honor_year = honor.getInt("year");
                String honor_name = honor.getString("name");
                System.out.println(honor_year+" : "+ honor_name);
            }
            }catch(Exception e) 
            {
                System.out.println(e.getMessage());
            }        
        }

    2.2 fastjson解析

    fastjson是阿里巴巴开源产品之一,解析速度快。

    下载地址(maven仓库):https://mvnrepository.com/artifact/com.alibaba/fastjson/1.2.53

    • JSON字符串是简单对象类型,被大括号包围:

     当待解析的JSON字符串是简单对象类型的,即用大括号包围,此时采用JSONObject对象来处理:

        @Test
        public void test3() 
        {
            //简单对象类型
            String jsonStr = "{'name':'Misaya','position':'Mid','hero':':Twisted Fate'}";
            
            JSONObject json = JSON.parseObject(jsonStr);
            String name = json.getString("name");
            System.out.println(name);
            
            System.out.println(json);
        }

    • JSON字符串是数组类型,被中括号包围

    当待解析的JSON字符串是简单数组类型的,即用中括号包围,此时采用JSONArray对象来处理:

        @Test
        public void test4() 
        {
            //数组类型
            String jsonStr = "['元旦','五一','国庆','春节']";
            
            JSONArray json = JSON.parseArray(jsonStr);
            String first = (String) json.get(0);
            
            System.out.println(first);
            System.out.println(json);
        }

    • JSON字符串为混合类型,既有简单对象,又有数组,逐层解析
        @Test
        public void test5() 
        {
            //混合类型
            String jsonStr = "[{'name':'元旦','vacation':'3'},{'name':'五一','vacation':'7'},{'name':'国庆','vacation':'7'}]";
            
            JSONArray jsonArr = JSON.parseArray(jsonStr);
            
            JSONObject jsonObj1 = jsonArr.getJSONObject(0);
            System.out.println(jsonObj1);
        }

    • JSON字符串有对应的类时,对象的解析:
     1 /**
     2  * @Author {LearnAndGet}
     3  * @Time 2018年11月24日
     4  * @Discription:
     5  */
     6 import java.util.Arrays;
     7 import java.util.HashMap;
     8 
     9 public class Player {
    10     private String name;
    11     private int age;
    12     private HashMap Hero = new HashMap<String,String>();
    13     private String[] nickNames;
    14     private Honor[] Honors;
    15     
    16     public String getName() {
    17         return name;
    18     }
    19 
    20     public void setName(String name) {
    21         this.name = name;
    22     }
    23 
    24     public int getAge() {
    25         return age;
    26     }
    27 
    28     public void setAge(int age) {
    29         this.age = age;
    30     }
    31 
    32     public HashMap getHero() {
    33         return Hero;
    34     }
    35 
    36     public void setHero(HashMap hero) {
    37         Hero = hero;
    38     }
    39 
    40     public String[] getNickNames() {
    41         return nickNames;
    42     }
    43 
    44     public void setNickNames(String[] nickNames) {
    45         this.nickNames = nickNames;
    46     }
    47 
    48     public Honor[] getHonors() {
    49         return Honors;
    50     }
    51 
    52     public void setHonors(Honor[] honors) {
    53         Honors = honors;
    54     }
    55 
    56     
    57     @Override
    58     public String toString() {
    59         return "Player [name=" + name + ", age=" + age + ", Hero=" + Hero + ", nickNames=" + Arrays.toString(nickNames)
    60                 + ", Honors=" + Arrays.toString(Honors) + "]";
    61     }
    62 
    63 
    64     static class Honor
    65     {
    66         int year;
    67         String name;
    68         public int getYear() {
    69             return year;
    70         }
    71         public void setYear(int year) {
    72             this.year = year;
    73         }
    74         public String getName() {
    75             return name;
    76         }
    77         public void setName(String name) {
    78             this.name = name;
    79         }
    80         @Override
    81         public String toString() {
    82             return "Honor [year=" + year + ", name=" + name + "]";
    83         }
    84     }
    85     
    86 
    87 }
    View Code
        @Test
        public void Json2Obj() 
        {
            //待解析的json字符串
            String jsonString = "{'name':'卢本伟','age':24,'Hero':{'name':'Fizz','Position':'Mid','charactor':'killer'},'nickNames':['五五开','芦苇','white'],'Honors':[{'year':2011,'name':'TGA总决赛冠军'},{'year':2013,'name':'S3全球总决赛中国区冠军'},{'year':2013,'name':'S3全球总决赛亚军'}]}";
            
            Player p = JSON.parseObject(jsonString, Player.class);
            
            System.out.println(p);
            
        }

    2.3 jackson解析

    • 解析普通属性
          @Test
          public void getCustomProp() 
          {
              String jsonStr = "{"price":5000,"count":100,"function":[{"name":"camera","config":1500},{"name":"music","config":2000}]}";
              
              try 
              {
                  ObjectMapper objMap = new ObjectMapper();
                  
                  JsonNode root = objMap.readTree(jsonStr);
                  
                  //在根节点上的属性
                  int price = root.path("price").asInt();
                  int count = root.path("count").asInt();
                  System.out.println("price"+":"+price);
                  System.out.println("count"+":"+count);
                  
                  //在叶子节点上的属性
                  JsonNode node = root.path("function");
                  String    fun1_name = node.path(0).path("name").asText();
                  int fun1_config = node.path(0).path("config").asInt();
                  System.out.println("function1:"+fun1_name+":"+fun1_config);
                  
                  String    fun2_name = node.path(1).path("name").asText();
                  int fun2_config = node.path(1).path("config").asInt();
                  System.out.println("function2:"+fun2_name+":"+fun2_config);            
              }catch(Exception ex) 
              {
                  System.out.println(ex.getMessage());
              }
          }

    • 解析对象字符串
          //省略javaBean:Person的代码
        @Test
      public void json2obj() { String jsonStr = "{"name":"二狗","age":15,"idCard":"42125"}"; try { ObjectMapper objMapper = new ObjectMapper();
         //当反序列化json时,未知属性会引起的反序列化被打断,这里我们禁用未知属性打断反序列化功能 objMapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES,
      false); Person p = objMapper.readValue(jsonStr, Person.class); System.out.println(p); }catch(Exception e) { System.out.println(e.getMessage()); } }

        
    • 解析对象数组构成的字符串
      //省略 javaBean:Person代码
      /* * 解析对象数组构成的String */ @Test public void jackSonTest() { String jsonStr = "[{"name":"二狗","age":15,"idCard":"42125"},{"name":"铁柱","age":12,"idCard":"46521"}]"; try { ObjectMapper mapper = new ObjectMapper(); TreeNode treeNode = mapper.readTree(jsonStr); List<Person> persons = mapper.readValue(jsonStr, new TypeReference<List<Person>>(){}); for (Person person : persons) { System.out.println(person); } }catch(Exception e) { System.out.println(e.getMessage()); } }

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  • 原文地址:https://www.cnblogs.com/LearnAndGet/p/10009646.html
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