• Java多线程_生产者消费者模式


     

     

    package com.kuangshen.gaoji;
    
    //测试:生产者消费者模型 --> 利用缓冲区解决:管程法
    //生产者,消费者,产品,缓冲区
    public class TestPC {
        public static void main(String[] args) {
            SynContainer container = new SynContainer();
            new Productor(container).start();
            new Consumer(container).start();
        }
    }
    
    //生产者
    class Productor extends Thread {
        SynContainer container;
    
        public Productor(SynContainer container) {
            this.container = container;
        }
    
        //生产
        @Override
        public void run() {
            for (int i = 0; i < 100; i++) {
                container.push(new Chicken(i));
                System.out.println("生产了" + i + "只鸡");
            }
        }
    }
    
    //消费者
    class Consumer extends Thread {
        SynContainer container;
    
        public Consumer(SynContainer container) {
            this.container = container;
        }
    
        //消费
        @Override
        public void run() {
            for (int i = 0; i < 100; i++) {
                System.out.println("消费了--》" + container.pop().id + "只鸡");
            }
        }
    }
    
    //产品
    class Chicken {
        int id;
    
        public Chicken(int id) {
            this.id = id;
        }
    }
    
    //缓冲区
    class SynContainer {
        //需要一个容器大小
        Chicken[] chickens = new Chicken[10];
        //容器计数器
        int count = 0;
    
        //生产者放入产品
        public synchronized void push(Chicken chicken) {
            //如果容器满了,就需要等待消费者消费
            if (count == chickens.length) {
                //通知消费者消费,生产等待
                try {
                    this.wait();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
            //如果没有满,我们就需要丢入产品
            chickens[count] = chicken;
            count++;
            //可以通知消费者消费了
            this.notifyAll();
        }
    
        //消费者消费产品
        public synchronized Chicken pop() {
            //判断能否消费
            if (count == 0) {
                //等待生产者生产,消费者等待
                try {
                    this.wait();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
            //如果可以消费
            count--;
            Chicken chicken = chickens[count];
            //吃完了,通知生产者生产
            this.notifyAll();
            return chicken;
        }
    }

     

    package com.kuangshen.gaoji;
    
    //测试生产者消费者问题2:信号灯法,标志位解决
    public class TestPC2 {
        public static void main(String[] args) {
            TV tv = new TV();
            new Player(tv).start();
            new Watcher(tv).start();
        }
    }
    
    //生产者-->演员
    class Player extends Thread {
        TV tv;
    
        public Player(TV tv) {
            this.tv = tv;
        }
    
        @Override
        public void run() {
            for (int i = 0; i < 20; i++) {
                if (i % 2 == 0) {
                    this.tv.play("快乐大本营播放中");
                } else {
                    this.tv.play("抖音:记录美好生活");
                }
            }
        }
    }
    
    //消费者-->观众
    class Watcher extends Thread {
        TV tv;
    
        public Watcher(TV tv) {
            this.tv = tv;
        }
    
        @Override
        public void run() {
            for (int i = 0; i < 20; i++) {
                tv.watch();
            }
        }
    }
    
    //产品-->节目
    class TV {
        //演员表演,观众等待 T
        //观众观看,演员等待 F
        String voice; //表演的节目
        boolean flag = true;
    
        //表演
        public synchronized void play(String voice) {
            if (!flag) {
                try {
                    this.wait();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
            System.out.println("演员表演了:" + voice);
            //通知观众观看
            this.notifyAll();//通知唤醒
            this.voice = voice;
            this.flag = !this.flag;
        }
    
        //观看
        public synchronized void watch() {
            if (flag) {
                try {
                    this.wait();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
            System.out.println("观看了:" + voice);
            //通知演员表演
            this.notifyAll();
            this.flag = !this.flag;
        }
    }

     

     

    package com.kuangshen.gaoji;
    
    import java.util.concurrent.ExecutorService;
    import java.util.concurrent.Executors;
    
    //测试线程池
    public class TestPool {
        public static void main(String[] args) {
            //1.创建服务,创建线程池
            //newFixedThreadPool 参数为:线程池大小
            ExecutorService service = Executors.newFixedThreadPool(10);
            //执行
            service.execute(new MyThread());
            service.execute(new MyThread());
            service.execute(new MyThread());
            service.execute(new MyThread());
            //关闭连接
            service.shutdown();
        }
    }
    
    class MyThread implements Runnable {
    
        @Override
        public void run() {
            System.out.println(Thread.currentThread().getName());
        }
    }
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  • 原文地址:https://www.cnblogs.com/LEPENGYANG/p/15060223.html
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