• HZOI20190822模拟29题解


    题面:https://www.cnblogs.com/Juve/articles/11396238.html

    下面开始一句话题解:

    A:爬山:

    二分答案,check即可

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #include<cmath>
    #define int long long
    using namespace std;
    const int mod=1e9+7;
    int n,d,a,b,l,r,mid,ans;
    bool check(int m){
    	int p=abs(m-a),q=abs(m-b),x,y;
    	if(p%d==0) x=p/d;
    	else x=p/d+1;
    	if(q%d==0) y=q/d;
    	else y=q/d+1;
    	if(x+y<=n-1) return 1;
    	return 0;
    }
    signed main(){
    	scanf("%lld%lld%lld%lld",&n,&d,&a,&b);
    	if(d==0){
    		printf("%lld
    ",max(a,b));
    		return 0;
    	}
    	l=min(a,b)-n*d,r=max(a,b)+n*d;
    	ans=max(a,b);
    	while(l<=r){
    		mid=(l+r)>>1;
    		if(check(mid))
    			ans=max(ans,mid),l=mid+1;
    		else r=mid-1;
    	}
    	printf("%lld
    ",ans);
    	return 0;
    }
    

    B:学数数:

    离散化,单调栈,前缀和

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #include<cmath>
    #include<queue>
    #include<stack>
    #define int long long
    using namespace std;
    const int MAXN=1e5+5;
    int n,q,a[MAXN],b[MAXN],k,cnt,sum[MAXN];
    int sta[MAXN],top=0,l[MAXN],r[MAXN];
    char op[5];
    signed main(){
    	scanf("%lld%lld",&n,&q);
    	for(int i=1;i<=n;i++) scanf("%lld",&a[i]);
    	memcpy(b,a,sizeof(a));
    	sort(b+1,b+n+1);
    	cnt=unique(b+1,b+n+1)-b-1;
    	for(int i=1;i<=n;i++){
    		while(top!=0&&a[sta[top]]<=a[i]) top--;
    		if(top==0) l[i]=1;
    		else l[i]=sta[top]+1;
    		sta[++top]=i;
    	}
    	top=0;
    	for(int i=n;i>=1;i--){
    		while(top!=0&&a[sta[top]]<a[i]) top--;
    		if(top==0) r[i]=n;
    		else r[i]=sta[top]-1;
    		sta[++top]=i;
    	}
    	for(int i=1;i<=n;i++){
    		int pos=lower_bound(b+1,b+cnt+1,a[i])-b;
    		sum[pos]+=(i-l[i]+1)*(r[i]-i+1);
    	}
    	for(int i=2;i<=n;i++) sum[i]+=sum[i-1];
    	while(q--){
    		scanf("%s%lld",op,&k);
    		if(op[0]=='='){
    			int x=upper_bound(b+1,b+cnt+1,k)-b-1;
    			int y=lower_bound(b+1,b+cnt+1,k)-b;
    			if(x==y) printf("%lld
    ",sum[x]-sum[x-1]);
    			else puts("0");
    		}else if(op[0]=='<'){
    			int x=lower_bound(b+1,b+cnt+1,k)-b-1;
    			printf("%lld
    ",sum[x]);
    		}else{
    			int x=upper_bound(b+1,b+cnt+1,k)-b-1;
    			printf("%lld
    ",sum[cnt]-sum[x]);
    		}
    	}
    	return 0;
    }
    

    C:七十和十七

    推一个公式即可,加上快速幂

    #include<cstdio>
    #include<iostream>
    #include<algorithm>
    #define int long long
    using namespace std;
    const int MAXN=1e5+5;
    const int mod=1e9+7;
    int f[MAXN],n,bit[MAXN];
    int q_pow(int a,int b,int p){
    	int res=1;
    	while(b){
    		if(b&1) res=1ll*res*a%p;
    		a=1ll*a*a%p;
    		b>>=1;
    	}
    	return res%mod;
    }
    signed main(){
    	scanf("%lld",&n);
    	bit[0]=1;
    	for(int i=1;i<=n;i++) bit[i]=(bit[i-1]*2)%mod;
    	for(int i=1;i<=n;i++)
    		f[i]=(f[i-1]+(bit[i-1]-1)%mod*q_pow(i,mod-2,mod)%mod)%mod;
    	printf("%lld
    ",f[n]);
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/Juve/p/11396290.html
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