• [转] Try to use one var statement per scope in JavaScript


    JavaScript’s var statement declares and optionally initializes one or more variables in the scope of the current function (or as global variables when used outside a function). Since var accepts multiple declarations, separated by commas, there’s usually no reason to use it more than once per function; it’s just a waste of bytes and—especially if you redeclare variables inside a loop—CPU cycles.

    Overuse of var statements is one of the most common problems I see in JavaScript code. I was guilty of it myself for quite a while and it took me a long time to break the habit.

    Bad:

    function getElementsByClassName(className, tagName, root) {
      var elements = [];
      var root     = root || document;
      var tagName  = tagName || '*';
      var haystack = root.getElementsByTagName(tagName);
      var regex    = new RegExp('(?:^|\\s+)' + className + '(?:\\s+|$)');
     
      for (var i = 0, length = haystack.length; i < length; ++i) {
        var el = haystack[i];
     
        if (el.className && regex.test(el.className)) {
          elements.push(el);
        }
      }
     
      return elements;
    }
    

    There are several things wrong with the example above.

    The most obvious problem is that I’ve used the var statement no less than seven times. Somewhat less obvious, but far worse: I’ve used it inside a loop, which means that I’m unnecessarily redeclaring a variable on each iteration. I’ve also unnecessarily redeclared two variables that were passed in as function arguments.

    Naturally, there’s a much better way to do this.

    Good:

    function getElementsByClassName(className, tagName, root) {
      root    = root || document;
      tagName = tagName || '*';
    
      var elements = [],
          haystack = root.getElementsByTagName(tagName),
          length   = haystack.length,
          regex    = new RegExp('(?:^|\\s+)' + className + '(?:\\s+|$)'),
          el, i;
    
      for (i = 0; i < length; ++i) {
        el = haystack[i];
    
        if (el.className && regex.test(el.className)) {
          elements.push(el);
        }
      }
    
      return elements;
    }
    

    There are circumstances in which it is actually necessary to redeclare a variable within a single scope, but they’re very rare, and are more often than not a warning sign that you need to rethink the code you’re writing.

  • 相关阅读:
    Python -- Redis List
    Python --Redis Hash操作
    Python使用redis介绍
    缓存服务器
    linux python3获取ip地址
    Rabbitmq -- rpc
    Rabbitmq--topic
    Rabbitmq -- direct
    删除rabbitmq中持久化的队列和数据
    Exchange-fanout 广播模式
  • 原文地址:https://www.cnblogs.com/JulyZhang/p/1979619.html
Copyright © 2020-2023  润新知