• [BZOJ 1733] [Usaco2005 feb] Secret Milking Machine 【二分 + 最大流】


    题目链接:BZOJ - 1733

    题目分析

    直接二分这个最大边的边权,然后用最大流判断是否可以有 T 的流量。

    代码

    #include <iostream>
    #include <cstdlib>
    #include <cstdio>
    #include <cstring>
    #include <cmath>
    #include <algorithm>
     
    using namespace std;
     
    const int MaxN = 200 + 5, MaxM = 80000 + 5, INF = 999999999;
     
    inline int gmin(int a, int b) {return a < b ? a : b;}
    inline int gmax(int a, int b) {return a > b ? a : b;}
     
    int n, m, Ts, Top, Ans, S, T, Tot;
    int d[MaxN], Num[MaxN];
     
    struct Edge
    {
        int u, v, w, len;
        Edge *Next, *Other;
    } E[MaxM * 2], *P = E, *Point[MaxN], *Last[MaxN], *EA[MaxM];
     
    inline void AddEdge(int x, int y, int z)
    {
        Edge *Q = ++P; ++P; EA[++Top] = P;
        P -> u = x; P -> v = y; P -> len = z; 
        P -> Next = Point[x]; Point[x] = P; P -> Other = Q;
        Q -> u = y; Q -> v = x; Q -> len = z;
        Q -> Next = Point[y]; Point[y] = Q; Q -> Other = P;   
    }
     
    void Set_Edge(int x)
    {
        for (int i = 1; i <= Top; ++i)
        {
            if (EA[i] -> len <= x) EA[i] -> w = 1;
            else EA[i] -> w = 0;
            EA[i] -> Other -> w = 0;
        }
    }
     
    int DFS(int Now, int Flow)
    {
        if (Now == T) return Flow;
        int ret = 0;
        for (Edge *j = Last[Now]; j; j = j -> Next)
            if (j -> w && d[j -> u] == d[j -> v] + 1) 
            {
                Last[Now] = j;
                int p = DFS(j -> v, gmin(j -> w, Flow - ret));
                j -> w -= p; j -> Other -> w += p; ret += p;
                if (ret == Flow) return ret;    
            }
        if (d[S] >= Tot) return ret;
        if (--Num[d[Now]] == 0) d[S] = Tot;
        ++Num[++d[Now]];
        Last[Now] = Point[Now];
        return ret; 
    }
     
    bool Check()
    {
        int MaxFlow = 0;
        S = 1; T = n; Tot = n;
        memset(d, 0, sizeof(d));
        memset(Num, 0, sizeof(Num)); Num[0] = Tot;
        for (int i = 1; i <= Tot; ++i) Last[i] = Point[i];
        while (d[S] < Tot) MaxFlow += DFS(S, INF);
        if (MaxFlow >= Ts) return true;
        else return false;
    }
     
    int main()
    {
        scanf("%d%d%d", &n, &m, &Ts);
        int a, b, c;
        int l, r, mid;
        l = INF; r = -INF;
        Top = 0;
        for (int i = 1; i <= m; ++i)
        {
            scanf("%d%d%d", &a, &b, &c);
            AddEdge(a, b, c);
            AddEdge(b, a, c);
            l = gmin(l, c);
            r = gmax(r, c);
        }
        while (l <= r)
        {
            mid = (l + r) >> 1;
            Set_Edge(mid);
            if (Check()) 
            {
                Ans = mid;
                r = mid - 1;
            }
            else l = mid + 1;
        }
        printf("%d
    ", Ans);
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/JoeFan/p/4392991.html
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