codeforces(234.2.)A

思路：除了把它的六种结果都写出来，我想不到更好的方法了。这个题做得很乱，因为思路不够清晰，每个步骤都相似，数据要分得很明确，一不小心就错了。还有审题问题。

#include <iostream>
#include <stdio.h>
#include <string.h>
using namespace std;
const int maxn = 12 + 5;

int main()
{
    int t, n, m, u;
    char str[maxn];
    int num1[maxn], num2[maxn];
    scanf("%d", &t);
    for(int i = 0; i < t; i++){
        n = m = u = 0;
        memset(str, 0, sizeof(str));
        memset(num1, 0, sizeof(num1));
        memset(num2, 0, sizeof(num2));
        scanf("%s", str);
        for(int j = 0; j < 12; j++){
            if(str[j] == 'O')
                m++;
        }
        if(m == 12){
            printf("0\n");
            continue;
        }
        else{
        n = 1;
        num1[0] = 1, num2[0] = 12;

        for(int j = 0; j < 6; j++){
            m = 0;
            for(int k = j; k < 12; k = (k + 6)){
                if(str[k] == 'X')
                    m++;
                }
            if(m == 2){
                num1[1] = 2, num2[1] = 6;
                n++;
                break;
            }
            else
                continue;
        }

        for(int j = 0; j < 4; j++){
            m = 0;
            for(int k = j; k < 12; k = (k + 4)){
                if(str[k] == 'X')
                    m++;
                }
            if(m == 3){
                num1[2] = 3, num2[2] = 4;
                n++;
                break;
            }
            else
                continue;
        }

        for(int j = 0; j < 3; j++){
            m = 0;
            for(int k = j; k < 12; k = (k + 3)){
                if(str[k] == 'X')
                    m++;
                }
            if(m == 4){
                num1[3] = 4, num2[3] = 3;
                n++;
                break;
            }
            else
                continue;
        }

        for(int j = 0; j < 2; j++){
            m = 0;
            for(int k = j; k < 12; k = (k + 2)){
                if(str[k] == 'X')
                    m++;
                }
            if(m == 6){
                num1[4] = 6, num2[4] = 2;
                n++;
                break;
            }
            else
                continue;
        }

        m = 0;
        for(int j = 0; j < 12; j++){
            if(str[j] == 'X')
                m++;
        }
        if(m == 12){
            num1[5] = 12, num2[5] = 1;
            n++;
        }

        printf("%d", n);
        for(int j = 0; j <= 6 ; j++){
            if((num1[j] != 0) && (num2[j] != 0)){
                printf(" %dx%d", num1[j], num2[j]);
                u++;
            }
            else{
                if(u == n){
                    printf("\n");
                    break;
                }
                else
                    continue;
            }
        }
        }
    }
    return 0;
}