有时候需要在前台自定义对象，然后把对象封装在list中，在传送到后台，这样的思想也比较合理
1. 前台代码
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$scope.saveScore = function () { $scope.userScoreList = new Array();//自定义数组 angular.forEach ($scope.records, function (record, index) { if (record.score != null) { $scope.userScoreModel = {'userAnswerId': null,'score': null};//自定义对象结构 $scope.userScoreModel.userAnswerId = record.userAnswerId;//赋值 $scope.userScoreModel.score = record.score; $scope.userScoreList.push($scope.userScoreModel);//把对象封装在集合中 debugger; } }); if ($scope.userScoreList != null && $scope.userScoreList.length > 0) { var fd = new FormData();// 使用angularJS的FormData封装要传送的数据 var userScoreRecords = angular.toJson($scope.userScoreList);//把对象(集合)转换为json串 fd.append('userScoreRecords', userScoreRecords);//参数放入formData中 debugger;//使用 debugger模式查看传值情况 $http.post('/reviewProcess/save', fd, { //使用post方法 传送formdata对象 transformRequest: angular.identity, //使用angular传参认证 headers: { 'Content-Type': undefined //设置请求头 } }) .success(function (data){ toastr.success("success"); }) .error(function (data) { toastr.success("failed"); }); }}; |
2. 后台接收
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@ResponseBody @RequestMapping(value = "/reviewProcess/save", method = RequestMethod.POST) public void saveUserScore (@RequestParam("userScoreRecords") String userScoreRecords) { //使用requestparam接收前台传送的json串 System.out.println(userScoreRecords); ObjectMapper mapper = new ObjectMapper(); // 使用fastJson的ObjectMapper反序列化json串为对象 UserScoreModel record = null; try { JSONArray jsonArray = new JSONArray (userScoreRecords); //在后台把json串转换为json数组 for (int i =0; i < jsonArray.length(); i++) { record = mapper.readValue(jsonArray.getJSONObject(i).toString(), UserScoreModel.class); //获取json数组的json对象并且反序列化为对应的对象 System.out.println(record); // 得到对象后后台即可操作 } } catch (Exception e) { logger.error(e.getMessage(), e); } } |