模拟与高精度 P2670 扫雷游戏

题目

https://www.luogu.com.cn/problem/P2670

代码

#include<iostream>
#include<cstdio>
#include<string>
#include<cstring>
using namespace std;
int answer[200][200];
#define inf 500
int main()
{
    int n, m;
    string tmp;
    scanf("%d%d", &n, &m);
    for (int i = 0; i < n; i++)
    {
        cin >> tmp;
        for (int j = 0; j < m; j++)
        {
            if (tmp[j] == '*')
            {
                if (i - 1 >= 0 && j - 1 >= 0)answer[i - 1][j - 1]++;
                if (i - 1 >= 0)answer[i - 1][j]++;
                if ( j - 1 >= 0)answer[i][j - 1]++;
                answer[i][j] = -inf;
                if (i +1 <n && j -1>=0)answer[i + 1][j-1]++;
                if (i + 1 <n )answer[i + 1][j]++;
                if (i - 1 >= 0 && j + 1<m)answer[i - 1][j + 1]++;
                if ( j + 1 <m)answer[i][j + 1]++;
                if (i + 1 <n && j +1<m)answer[i + 1][j + 1]++;
            }
        }
    }
    for (int i = 0; i < n; i++)
    {
        for (int j = 0; j < m; j++)
        {
            if (answer[i][j] < 0)
                printf("*");
            else
                printf("%d", answer[i][j]);
        }
        printf("
");
    }


}