• PAT (Advanced Level) Practice 1069 The Black Hole of Numbers (20分)


    1.题目

    For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the second number from the first one. Repeat in this manner we will soon end up at the number 6174 -- the black hole of 4-digit numbers. This number is named Kaprekar Constant.

    For example, start from 6767, we'll get:

    7766 - 6677 = 1089
    9810 - 0189 = 9621
    9621 - 1269 = 8352
    8532 - 2358 = 6174
    7641 - 1467 = 6174
    ... ...
    

    Given any 4-digit number, you are supposed to illustrate the way it gets into the black hole.

    Input Specification:

    Each input file contains one test case which gives a positive integer N in the range (0,10​4​​).

    Output Specification:

    If all the 4 digits of N are the same, print in one line the equation N - N = 0000. Else print each step of calculation in a line until 6174 comes out as the difference. All the numbers must be printed as 4-digit numbers.

    Sample Input 1:

    6767
    

    Sample Output 1:

    7766 - 6677 = 1089
    9810 - 0189 = 9621
    9621 - 1269 = 8352
    8532 - 2358 = 6174
    

    Sample Input 2:

    2222
    

    Sample Output 2:

    2222 - 2222 = 0000
    

    2.题目分析

    PAT (Basic Level) Practice 1019 数字黑洞 (20分) (string、int转换+sort排序)

    3.代码

    #include<iostream>
    #include<algorithm>
    #include<string>
    #include<cstring>
    #include<sstream>
    #include<functional>
    using namespace std;
    int main()
    {
    	string number;	
    	cin >> number;
    	
    	string min = number;
    	string max = number;
    
    	while (1)
    	{
    			min = number;
    			max = number;
    			while (min.length() < 4)
    				min.append("0");
    			while (max.length() < 4)
    				max.append("0");
    		sort(min.begin(), min.end(), less<char>());
    		sort(max.begin(), max.end(), greater<char>());
    		int minn = 0, maxx = 0;
    		stringstream ss;
    		ss << min;
    		ss >> minn;
    		stringstream ss2;
    		ss2 << max;
    		ss2 >> maxx;
    		int numberr = maxx - minn;
    		if (numberr == 0)
    		{
    			cout << max << ' ' << '-' << ' ' << min << ' ' << '=' << ' ' << "0000" << endl; break;
    		}
    		stringstream ss3;
    		ss3 << (maxx - minn);
    		ss3 >> number;
    		for (int i = number.length(); i < 4; i++)
    			number = "0" + number;
    		cout << max << ' ' << '-' << ' ' << min << ' ' << '=' << ' ' << number << endl;
    		if (number == "6174")break;
    	}
    }
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  • 原文地址:https://www.cnblogs.com/Jason66661010/p/12788819.html
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