P5057 [CQOI2006]简单题 前缀异或差分/树状数组

好思路，好思路。。。

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思路：前缀异或差分

提交：1次

题解：区间修改，单点查询，树状数组，如思路$qwq$

#include<cstdio>
#include<iostream> 
using namespace std;
#define R register int 
#define ull unsigned long long
#define ll long long
#define pause (for(R i=1;i<=10000000000;++i))
#define In freopen("NOIPAK++.in","r",stdin)
#define Out freopen("out.out","w",stdout)
namespace Fread {
static char B[1<<15],*S=B,*D=B;
#ifndef JACK
#define getchar() (S==D&&(D=(S=B)+fread(B,1,1<<15,stdin),S==D)?EOF:*S++)
#endif
inline int g() {
    R ret=0,fix=1; register char ch; while(!isdigit(ch=getchar())) fix=ch=='-'?-1:fix;
    if(ch==EOF) return EOF; do ret=ret*10+(ch^48); while(isdigit(ch=getchar())); return ret*fix;
} inline bool isempty(const char& ch) {return (ch<=36||ch>=127);}
inline void gs(char* s) {
    register char ch; while(isempty(ch=getchar()));
    do *s++=ch; while(!isempty(ch=getchar()));
}
} using Fread::g; using Fread::gs;

namespace Luitaryi {
const int N=100010;
int n,m;
int c[N];
inline int lbt(int x) {return x&-x;}
inline void add(int pos) {for(;pos<=n;pos+=lbt(pos)) c[pos]^=1;}
inline int query(int pos) { R ret=0;
    for(;pos;pos-=lbt(pos)) ret^=c[pos]; return ret;
}
inline void main() {
    n=g(),m=g();
    while(m--) {
        R op=g(),l,r; if(op&1) l=g(),r=g(),add(l),add(r+1);
        else l=g(),printf("%d
",query(l));
    }
}
}
signed main() {
    Luitaryi::main();
    return 0;
}

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2019.07.17