• android访问webservice


       // nameSpace 命名空间,methodName:方法名字;maps:参数集合;webserviceUrl:访问的webservice的网址;比如:http://17.18.199.100:80805/doReqToWebWs.asmx
        private String ws(String nameSpace,String methodName,HashMap<String,String> maps,String webserviceUrl){
            String result="";
            try{
                SoapObject request=new SoapObject(nameSpace,methodName);//NameSpace
    
                //webService方法中的参数,这个根据你的webservice来,可以没有。
                //但请注意,参数名称和参数类型客户端和服务端一定要一致,否则将可能获取不到你想要的
                Iterator<String> it = maps.keySet().iterator();
                while (it.hasNext()) {
                    String keyString = it.next();
                    request.addProperty(keyString, maps.get(keyString));
                }
    
                SoapSerializationEnvelope envelope=new SoapSerializationEnvelope(
                        SoapEnvelope.VER11);
    
                envelope.dotNet=true;
    
                envelope.setOutputSoapObject(request);
    
                HttpTransportSE ht=new HttpTransportSE(webserviceUrl);
    
                ht.call(nameSpace + methodName, envelope);
    
                if(envelope.getResponse()!=null){
                    SoapPrimitive response=(SoapPrimitive)envelope.getResponse();
                    result=response.toString();//这里获得了webService的返回值
                    Log.e("resultCode",result);
                }
    
            }catch(Exception e){
                result=e.getMessage();
                Log.e("resultCode22",result);
            }
            return result;
        }
    

      

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  • 原文地址:https://www.cnblogs.com/Jackie-zhang/p/6164692.html
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