https://leetcode.com/problems/find-eventual-safe-states/description/
class Solution { public: vector<bool> visited; vector<int> mem; // -1 unknown, 0 unsafe, 1 safe. int n; vector<int> eventualSafeNodes(vector<vector<int>>& graph) { n = graph.size(); mem = vector<int>(n, -1); visited = vector<bool>(n, false); for (int i = 0; i < n; i++) dfs(graph, i); vector<int> res; for (int i = 0; i < n; i++) if (mem[i] == 1) res.push_back(i); return res; } bool dfs(vector<vector<int>>& graph, int i) { // check if i is evetually safe if (mem[i] != -1) return mem[i] == 1; bool res = true; if (visited[i]) { // A loop res = false; } else { visited[i] = true; for (auto j : graph[i]) { if (!dfs(graph, j)) { res = false; break; } } // visited[i] = false; // This line is optional, since we've cached the result for i in mem. } mem[i] = res; return res; } };