• POJ 2251 Dungeon Master


    习惯用双广了,这次WA了好几次,标记起和终止始节点时发现了错误,后来没改彻底,具体见注释行。

    双广速度快,空间小,结构也相对 bfs 简单;

    # include <stdio.h>
    # include <string.h>
    
    typedef struct {char l, r, c;}Pos;  /* char 足够了,比较时没出错 */
    
    const int dir[][3] = {{0,0,1}, {0,0,-1}, {0,1,0}, {0,-1,0}, {1,0,0}, {-1,0,0}};
    
    Pos start, goal;
    char L, R, C;
    char dun[35][35][35];
    char vis[35][35][35];
    short dis[35][35][35];
    
    char read_data(void)
    {
        char f1, f2;
        int i, j, k;
        
        if (~scanf("%d%d%d", &L, &R, &C)) return 0;
        if (L==0 && R==0 && C==0) return 0;
        f1 = f2 = 1;
        for (i = 1; i <= L; ++i)
        for (j = 1; j <= R; ++j)
        {
            scanf("%s", dun[i][j]+1);
            for (k = 1; f1 && k<=C; ++k)
                if (dun[i][j][k] == 'S')
                {
                    f1 = 0;
                    start.l = i;      /* WA: start.l = 1 */
                    start.r = j;
                    start.c = k;
                    break;
                }
            for (k = 1; f2 && k<=C; ++k)
                if (dun[i][j][k] == 'E')
                {
                    f2 = 0;
                    goal.l = i;   /* WA: goal.l = L */
                    goal.r = j;
                    goal.c = k;
                    break;
                }
        }
        
        return 1;
    }
    
    int bfs(void)
    {
        Pos Q[30000], cur, nst;
        char nl, nr, nc;
        int front, rear, i;
        
        memset(vis, 0, sizeof(vis));  /* WA vis必须要清空,dis则不是必须的 */
        
        front = 1;
        rear = 3;
        
        Q[1] = start;
        Q[2] = goal;
        
        vis[start.l][start.r][start.c] = 1;
        vis[ goal.l][ goal.r][ goal.c] = 2;
        
        dis[start.l][start.r][start.c] = 0;
        dis[ goal.l][ goal.r][ goal.c] = 0;
        
        while (front < rear)
        {
            cur = Q[front++];
            for (i = 0; i < 6; ++i)
            {
                nl = cur.l + dir[i][0];
                nr = cur.r + dir[i][1];
                nc = cur.c + dir[i][2];
                if (1<=nl&&nl<=L && 1<=nr&&nr<=R && 1<=nc&&nc<=C && dun[nl][nr][nc]!='#')
                {
                    if (!vis[nl][nr][nc])
                    {                    
                        nst.l = nl, nst.r = nr, nst.c = nc;
                        Q[rear++] = nst;
                        vis[nl][nr][nc] = vis[cur.l][cur.r][cur.c];
                        dis[nl][nr][nc] = dis[cur.l][cur.r][cur.c] + 1;
                    }
                    else if (vis[cur.l][cur.r][cur.c] != vis[nl][nr][nc])
                    {
                        return dis[cur.l][cur.r][cur.c] + dis[nl][nr][nc] + 1;
                    }
                }
            }
        }
        
        return -1;
    }
    
    void solve(void)
    {
        int ans;
        
        ans = bfs();
        if (ans == -1) puts("Trapped!");
        else printf("Escaped in %d minute(s).\n", ans);
    }
    
    int main()
    {
        while (read_data())
        {
            solve();
        }
        
        return 0;
    }

    .

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  • 原文地址:https://www.cnblogs.com/JMDWQ/p/2539072.html
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