• [BZOJ2157]旅游(树链剖分/LCT)


    树剖裸题,当然LCT也可以。

    树剖:

      1 #include<cstdio>
      2 #include<algorithm>
      3 #define ls (x<<1)
      4 #define rs (ls|1)
      5 #define lson ls,L,mid
      6 #define rson rs,mid+1,R
      7 #define rep(i,l,r) for (int i=(l); i<=(r); i++)
      8 #define For(i,x) for (int i=h[x],k; i; i=nxt[i])
      9 using namespace std;
     10 
     11 const int N=20010;
     12 char op[10];
     13 int n,Q,u,v,w,tim,cnt,id[N],z[N],pos[N],pre[N],fa[N],dep[N],sz[N],son[N],top[N],dfn[N];
     14 int h[N],to[N<<1],nxt[N<<1],val[N<<1],mn[N<<2],mx[N<<2],sm[N<<2],tag[N<<2];
     15 
     16 void add(int u,int v,int w){ to[++cnt]=v; val[cnt]=w; nxt[cnt]=h[u]; h[u]=cnt; }
     17 
     18 void dfs(int x){
     19     sz[x]=1; dep[x]=dep[fa[x]]+1;
     20     For(i,x) if ((k=to[i])!=fa[x]){
     21         fa[k]=x; pre[k]=val[i]; id[val[i]]=k; dfs(k); sz[x]+=sz[k];
     22         if (sz[k]>sz[son[x]]) son[x]=k;
     23     }
     24 }
     25 
     26 void dfs2(int x,int tp){
     27     top[x]=tp; dfn[x]=++tim; pos[tim]=x;
     28     if (son[x]) dfs2(son[x],tp);
     29     For(i,x) if ((k=to[i])!=fa[x] && k!=son[x]) dfs2(k,k);
     30 }
     31 
     32 void upd(int x){ sm[x]=sm[ls]+sm[rs]; mx[x]=max(mx[ls],mx[rs]); mn[x]=min(mn[ls],mn[rs]); }
     33 void put(int x){ sm[x]=-sm[x]; int t=mx[x]; mx[x]=-mn[x]; mn[x]=-t; tag[x]^=1; }
     34 
     35 void push(int x){ if (tag[x]) put(ls),put(rs),tag[x]=0; }
     36 
     37 void build(int x,int L,int R){
     38     if (L==R){ sm[x]=mn[x]=mx[x]=z[pre[pos[L]]]; return; }
     39     int mid=(L+R)>>1;
     40     build(lson); build(rson); upd(x);
     41 }
     42 
     43 void mdf(int x,int L,int R,int p,int k){
     44     if (L==R){ sm[x]=mn[x]=mx[x]=k; return; }
     45     int mid=(L+R)>>1; push(x);
     46     if (p<=mid) mdf(lson,p,k); else mdf(rson,p,k);
     47     upd(x);
     48 }
     49 
     50 void Rev(int x,int L,int R,int l,int r){
     51     if (L==l && r==R){ put(x); return; }
     52     int mid=(L+R)>>1; push(x);
     53     if (r<=mid) Rev(lson,l,r);
     54     else if (l>mid) Rev(rson,l,r);
     55         else Rev(lson,l,mid),Rev(rson,mid+1,r);
     56     upd(x);
     57 }
     58 
     59 int que(int x,int L,int R,int l,int r,int k){
     60     if (L==l && r==R) return k==2?mn[x]:k?mx[x]:sm[x];
     61     int mid=(L+R)>>1; push(x);
     62     if (r<=mid) return que(lson,l,r,k);
     63     else if (l>mid) return que(rson,l,r,k);
     64         else{
     65             int mid=(L+R)>>1,t1=que(lson,l,mid,k),t2=que(rson,mid+1,r,k);
     66             return k==2 ? min(t1,t2) : k==1 ? max(t1,t2) : t1+t2;
     67         }
     68 }
     69 
     70 void work(int x,int y){
     71     for (; top[x]!=top[y]; x=fa[top[x]]){
     72         if (dep[top[x]]<dep[top[y]]) swap(x,y);
     73         Rev(1,1,n,dfn[top[x]],dfn[x]);
     74     }
     75     if (x==y) return;
     76     if (dep[x]<dep[y]) swap(x,y);
     77     Rev(1,1,n,dfn[y]+1,dfn[x]);
     78 }
     79 
     80 int solve(int x,int y,int k){
     81     int res=0;
     82     if (k==1) res=-1001;
     83     if (k==2) res=1001;
     84     for (; top[x]!=top[y]; x=fa[top[x]]){
     85         if (dep[top[x]]<dep[top[y]]) swap(x,y);
     86         int t=que(1,1,n,dfn[top[x]],dfn[x],k);
     87         if (k==0) res+=t;
     88         if (k==1) res=max(res,t);
     89         if (k==2) res=min(res,t);
     90     }
     91     if (x==y) return res;
     92     if (dep[x]<dep[y]) swap(x,y);
     93     int t=que(1,1,n,dfn[y]+1,dfn[x],k);
     94     if (k==0) res+=t;
     95     if (k==1) res=max(res,t);
     96     if (k==2) res=min(res,t);
     97     return res;
     98 }
     99 
    100 int main(){
    101     freopen("bzoj2157.in","r",stdin);
    102     freopen("bzoj2157.out","w",stdout);
    103     scanf("%d",&n);
    104     rep(i,2,n) scanf("%d%d%d",&u,&v,&w),u++,v++,add(u,v,i),add(v,u,i),z[i]=w;
    105     dfs(1); dfs2(1,1); build(1,1,n);
    106     for (scanf("%d",&Q); Q--; ){
    107         scanf("%s%d%d",op,&u,&v); u++; v++;
    108         if (op[0]=='C') mdf(1,1,n,dfn[id[u]],v-1);
    109         if (op[0]=='N') work(u,v);
    110         if (op[0]=='S') printf("%d
    ",solve(u,v,0));
    111         if (op[1]=='A') printf("%d
    ",solve(u,v,1));
    112         if (op[1]=='I') printf("%d
    ",solve(u,v,2));
    113     }
    114     return 0;
    115 }

    LCT:

     1 #include<cstdio>
     2 #include<algorithm>
     3 #define ls c[x][0]
     4 #define rs c[x][1]
     5 #define rep(i,l,r) for (int i=(l); i<=(r); i++)
     6 using namespace std;
     7 
     8 const int N=40010;
     9 char op[10];
    10 int n,Q,nd,x,y,w,v[N],c[N][2],f[N],rev[N],tag[N],sm[N],mn[N],mx[N];
    11 
    12 bool isrt(int x){ return !f[x] || (c[f[x]][0]!=x && c[f[x]][1]!=x); }
    13 
    14 void upd(int x){
    15     sm[x]=sm[ls]+sm[rs]+v[x];
    16     mn[x]=min(min(mn[ls],mn[rs]),x>n?v[x]:1001);
    17     mx[x]=max(max(mx[ls],mx[rs]),x>n?v[x]:-1001);
    18 }
    19 
    20 void put(int x){ if (!x) return; v[x]=-v[x]; sm[x]=-sm[x]; int t=mx[x]; mx[x]=-mn[x]; mn[x]=-t; tag[x]^=1; }
    21 void Rev(int x){ if (!x) return; rev[x]^=1; swap(ls,rs); }
    22 
    23 void push(int x){
    24     if (rev[x]) Rev(ls),Rev(rs),rev[x]=0;
    25     if (tag[x]) put(ls),put(rs),tag[x]=0;
    26 }
    27 
    28 void pd(int x){ if (!isrt(x)) pd(f[x]); push(x); }
    29 
    30 void rot(int x){
    31     int y=f[x],z=f[y],w=c[y][1]==x;
    32     if (!isrt(y)) c[z][c[z][1]==y]=x;
    33     f[x]=z; f[y]=x; f[c[x][w^1]]=y;
    34     c[y][w]=c[x][w^1]; c[x][w^1]=y; upd(y);
    35 }
    36 
    37 void splay(int x){
    38     for (pd(x); !isrt(x); rot(x)){
    39         int y=f[x],z=f[y];
    40         if (!isrt(y)) rot((c[z][0]==y)^(c[y][0]==x) ? x : y);
    41     }upd(x);
    42 }
    43 
    44 void access(int x){ for (int y=0; x; y=x,x=f[x]) splay(x),c[x][1]=y,upd(x); }
    45 void mkrt(int x){ access(x); splay(x); Rev(x); }
    46 int split(int x,int y){ mkrt(x); access(y); splay(y); return y; }
    47 void link(int x,int y){ mkrt(x); f[x]=y; }
    48 
    49 int main(){
    50     freopen("bzoj2157.in","r",stdin);
    51     freopen("bzoj2157.out","w",stdout);
    52     scanf("%d",&n);
    53     rep(i,0,n) mn[i]=1001,mx[i]=-1001;
    54     rep(i,1,n-1) scanf("%d%d%d",&x,&y,&w),x++,y++,v[n+i]=w,upd(n+i),link(n+i,x),link(n+i,y);
    55     for (scanf("%d",&Q); Q--; ){
    56         scanf("%s%d%d",op,&x,&y); x++; y++;
    57         if (op[0]=='C') splay(x+n-1),v[x+n-1]=y-1,upd(x+n-1);
    58         if (op[0]=='N') put(split(x,y));
    59         if (op[0]=='S') printf("%d
    ",sm[split(x,y)]);
    60         if (op[1]=='A') printf("%d
    ",mx[split(x,y)]);
    61         if (op[1]=='I') printf("%d
    ",mn[split(x,y)]);
    62     }
    63     return 0;
    64 }
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  • 原文地址:https://www.cnblogs.com/HocRiser/p/11177928.html
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