• CodeForces


    You are given an array a consisting of n integers.

    Your task is to determine if a has some subsequence of length at least 3 that is a palindrome.

    Recall that an array b is called a subsequence of the array a if b can be obtained by removing some (possibly, zero) elements from a (not necessarily consecutive) without changing the order of remaining elements. For example, [2], [1,2,1,3] and [2,3] are subsequences of [1,2,1,3], but [1,1,2] and [4] are not.

    Also, recall that a palindrome is an array that reads the same backward as forward. In other words, the array a of length n is the palindrome if ai=an−i−1 for all i from 1 to n. For example, arrays [1234], [1,2,1], [1,3,2,2,3,1] and [10,100,10] are palindromes, but arrays [1,2] and [1,2,3,1] are not.

    You have to answer t independent test cases.

    Input
    The first line of the input contains one integer t (1≤t≤100) — the number of test cases.

    Next 2t lines describe test cases. The first line of the test case contains one integer n (3≤n≤5000) — the length of a. The second line of the test case contains n integers a1,a2,…,an (1≤ai≤n), where ai is the i-th element of a.

    It is guaranteed that the sum of n over all test cases does not exceed 5000 (∑n≤5000).

    Output
    For each test case, print the answer — “YES” (without quotes) if a has some subsequence of length at least 3 that is a palindrome and “NO” otherwise.

    Example
    Input
    5
    3
    1 2 1
    5
    1 2 2 3 2
    3
    1 1 2
    4
    1 2 2 1
    10
    1 1 2 2 3 3 4 4 5 5
    Output
    YES
    YES
    NO
    YES
    NO
    Note
    In the first test case of the example, the array a has a subsequence [1,2,1] which is a palindrome.

    In the second test case of the example, the array a has two subsequences of length 3 which are palindromes: [2,3,2] and [2,2,2].

    In the third test case of the example, the array a has no subsequences of length at least 3 which are palindromes.

    In the fourth test case of the example, the array a has one subsequence of length 4 which is a palindrome: [1,2,2,1] (and has two subsequences of length 3 which are palindromes: both are [1,2,1]).

    In the fifth test case of the example, the array a has no subsequences of length at least 3 which are palindromes.

    题目大意:多组测试样例。对于每组测试样例,输入n,然后输入n个数,可以删除这个数组中任意元素,判断这个数组是不是回文数组,(回文数组可以是【1,2,1】,【1,2,3,2,1】)。

    解题思路:因为n是大于等于三的,我们输入的时候判断一下,如果n小于3直接出no就可以了,我们可以以1到n-1中的数作分割,然后判断 i 前面的数和 i 后面的数是否有重合,如果重合则说明一定是个回文数组,我们设一个标记数组,再设一个flag判断是否为回文数组,每次都将 i 之前的数全部置为true,后面如果遇到了true则将flag置为yes并退出循环,最后根据flag的值来确定是不是一个回文数组。AC代码:

    #include <cstdio>
    #include <iostream>
    #include <algorithm>
    #include <cstring>
    using namespace std;
    const int N=5e3+50;
    int a[N];
    bool book[N];
    int main()
    {
    	int t;
    	cin>>t;
    	while(t--)
    	{
    		int n;
    	 	cin>>n;
    		if(n<3)
    		{
    			cout<<"NO"<<endl;
    			continue;
    		}
    		memset(book,false,sizeof book);
    		for(int i=0;i<n;i++)
    		  cin>>a[i];
    		bool flag=false;
    		for(int i=1;i<n;i++)//以第i个数为分割
    		{
    			for(int j=0;j<i;j++)//标记i前面的数
    			  book[a[j]]=true;
    			for(int j=i+1;j<n;j++)//判断i后面的数
    			  if(book[a[j]])
    			  {
    				  flag=true;
    				   break;
    			  }
    			if(flag)
    			  break;  
    		}
    		if(flag)
    		  cout<<"YES"<<endl;
    		else
    		  cout<<"NO"<<endl;
    	}
    	//system("pause");
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/Hayasaka/p/14294286.html
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