题目连接
http://acm.hdu.edu.cn/showproblem.php?pid=5104
Primes Problem
Description
Given a number n, please count how many tuple$(p_1, p_2, p_3)$ satisfied that $p_1 leq p_2 leq p_3, $ $p_1,p_2,p_3$ are primes and $p_1 + p_2 + p_3 = n$.
Input
Multiple test cases(less than 100), for each test case, the only line indicates the positive integer $n (n leq 10000).$
Output
For each test case, print the number of ways.
Sample Input
3
9
Sample Output
0
2
简单题如下。。
1 #include<algorithm> 2 #include<iostream> 3 #include<cstdlib> 4 #include<cstring> 5 #include<cstdio> 6 #include<vector> 7 #include<map> 8 #include<set> 9 using std::cin; 10 using std::cout; 11 using std::endl; 12 using std::find; 13 using std::sort; 14 using std::set; 15 using std::map; 16 using std::pair; 17 using std::vector; 18 using std::multiset; 19 using std::multimap; 20 #define pb(e) push_back(e) 21 #define sz(c) (int)(c).size() 22 #define mp(a, b) make_pair(a, b) 23 #define all(c) (c).begin(), (c).end() 24 #define iter(c) decltype((c).begin()) 25 #define cls(arr,val) memset(arr,val,sizeof(arr)) 26 #define cpresent(c, e) (find(all(c), (e)) != (c).end()) 27 #define rep(i, n) for (int i = 0; i < (int)(n); i++) 28 #define tr(c, i) for (iter(c) i = (c).begin(); i != (c).end(); ++i) 29 const int N = 10010; 30 typedef unsigned long long ull; 31 bool P[N]; 32 int tot, prime[1500]; 33 bool isPrim(int n) { 34 for (int i = 2; i * i <= n; i++) if (n % i == 0) return false; 35 return n != 1; 36 } 37 inline void init() { 38 for (int i = 1; i < N;i++) { 39 if (isPrim(i)) prime[tot++] = i, P[i] = true; 40 else P[i] = false; 41 } 42 } 43 inline void solve(int n) { 44 int res = 0; 45 for (int i = 0; i < tot && prime[i] < n; i++) { 46 for (int j = i; j < tot && prime[j] < n; j++) { 47 int t = n - prime[i] - prime[j]; 48 if (t >= prime[j] && P[t]) res++; 49 } 50 } 51 printf("%d ", res); 52 } 53 int main() { 54 #ifdef LOCAL 55 freopen("in.txt", "r", stdin); 56 freopen("out.txt", "w+", stdout); 57 #endif 58 int n; 59 init(); 60 while (~scanf("%d", &n)) { 61 solve(n); 62 } 63 return 0; 64 }