• bzoj 1012 [JSOI2008]最大数maxnumber


    原题链接:http://www.lydsy.com/JudgeOnline/problem.php?id=1012 
    线段树,单点更新。。

     1 #include<algorithm>
     2 #include<iostream>
     3 #include<cstdlib>
     4 #include<cstdio>
     5 #define lc root<<1
     6 #define rc root<<1|1
     7 using std::max;
     8 const int Max_N = 200010;
     9 const int INF = 0x3f3f3f3f;
    10 int MOD;
    11 struct Node { int val; };
    12 struct SegTree {
    13     Node seg[Max_N << 2];
    14     inline void push_up(int root) {
    15         seg[root].val = max(seg[lc].val, seg[rc].val);
    16     }
    17     inline void update(int root, int l, int r, int pos, int t) {
    18         if (pos > r || pos < l) return;
    19         if (pos <= l && pos >= r) {
    20             seg[root].val += t;
    21             return;
    22         }
    23         int mid = (l + r) >> 1;
    24         update(lc, l, mid, pos, t);
    25         update(rc, mid + 1, r, pos, t);
    26         push_up(root);
    27     }
    28     inline int query(int root, int l, int r, int x, int y) {
    29         if (x > r || y < l) return -INF;
    30         if (x <= l && y >= r) return seg[root].val;
    31         int mid = (l + r) >> 1;
    32         int v1 = query(lc, l, mid, x, y);
    33         int v2 = query(rc, mid + 1, r, x, y);
    34         return max(v1, v2);
    35     }
    36 }seg;
    37 int main() {
    38 #ifdef LOCAL
    39     freopen("in.txt", "r", stdin);
    40     freopen("out.txt", "w+", stdout);
    41 #endif
    42     char ch;
    43     int n, v, res, len = 0;
    44     while (~scanf("%d %d", &n, &MOD)) {
    45         res = 0;
    46         for (int i = 0; i < n; i++) {
    47             getchar();
    48             scanf("%c %d", &ch, &v);
    49             if (ch == 'A') ++len, seg.update(1, 1, n, len, (res + v) % MOD);
    50             else printf("%d
    ", res = seg.query(1, 1, n, len - v + 1, n));
    51         }
    52     }
    53     return 0;
    54 }
    View Code
    By: GadyPu 博客地址:http://www.cnblogs.com/GadyPu/ 转载请说明
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  • 原文地址:https://www.cnblogs.com/GadyPu/p/4526576.html
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